Optimisation
Demand: y = 800 - 5x
Maximise z = (x - 40)y --> objective
Subject to y + 5x = 800 --> constraint
Demand model
Inputs
Max deman 800
Slope -5
Unit cost R 40
Decision
Price R100
Demand 300
Constraint Y+5X
Demand R800 <= 800
Outcome
Profit R18,000
Demand: y = 800 - 5x
Maximise z = (x - 40)y --> objective
Subject to y + 5x = 800 --> constraint
Demand model
Inputs
Max deman 800
Slope -5
Unit cost R 40
Decision
Price R100
Demand 300
Constraint Y+5X
Demand R800 <= 800
Outcome
Profit R18,000