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Examen

Test Bank For Henkes Med Math Dosage Calculation, Preparation, and Administration, 9th Edition (Buchholz, 2020), Chapter 1-10 | 9781975106522 | All Chapters with Answers and Rationals

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Test Bank For Henkes Med Math Dosage Calculation, Preparation, and Administration, 9th Edition (Buchholz, 2020), Chapter 1-10 | 9781975106522 | All Chapters with Answers and Rationals

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Información del documento

Subido en
21 de agosto de 2025
Número de páginas
144
Escrito en
2025/2026
Tipo
Examen
Contiene
Preguntas y respuestas

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Vista previa del contenido

,
,Chapter 1: Arithmetic Needed for Dosage
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MULTIPLE CHOICE oo




1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


drink 15 oz. What portion of the water remained?
oo oo oo oo oo oo oo oo oo


a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A o o


Feedback: Subtract the quantity of water the client drank (15 oz) from the total available
oo oo oo oo oo oo oo oo oo oo oo oo oo oo


quantity (25 oz): 10 oz remain. To determine the portion of the water that remains, create a
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fraction by dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided
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by 25 = 10/25. To reduce fractions, find the largest number that can be divided evenly into
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the numerator and the denominator
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(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms
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of 2/5.
oo oo




Format: Multiple oo


Choice Chapter: 1
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Client Needs: Physiological Integrity: Basic Care and Comfort
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Cognitive Level: Apply
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Difficulty: Moderate oo


Page and Header: 2, Dividing Whole Numbers; 3, Fractions
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Integrated Process: Teaching/Learning
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Objective: 1, 2 oo oo




2. A patient/client was prescribed 240 W
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suSreMb.yWmSouth as a supplement but consumed
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only 100 mL. What portion of the Ensure remained?
oo oo oo oo oo oo oo oo oo


a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B o o


Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total
oo oo oo oo oo oo oo oo oo oo oo oo oo


available quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that
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remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion).
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Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the largest number that can be
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


divided evenly into the numerator and the denominator (20); 140 divided by 20 (140/20) = 7;
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240/20 = 12. The fraction 140/240 can be reduced to its lowest terms of 7/12.
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo




Format: Multiple oo


Choice Chapter: 1
oo oo oo


Client Needs: Physiological Integrity: Basic Care and Comfort
oo oo oo oo oo oo oo


Cognitive Level: Apply
oo oo oo


Difficulty: Moderate oo


Page and Header: 2, Dividing Whole Numbers; 3, Fractions
oo oo oo oo oo oo oo oo


Integrated Process: Teaching/Learning
oo oo oo


Objective: 1, 2 oo oo




1|Page

, 3. A patient/client consumed
oo oz. of coffee, 2/3 oz. of ice cream, and
oo oz. of beef o o o o oo oo oo oo oo oo oo oo o o o o oo oo


broth. What is the total number of ounces consumed that should be documented for the
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


patient/client?
oo


a. 3 3/4 oo


b. 4 5/12 oo


c. 4 2/3 oo


d. 4 4/9 oo




ANS: B o o


Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


multiplying the whole number by the denominator and then adding that total to the numerator. For
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the coffee, 4  2 = 8 + 1 = 9/4; for the beef broth, 2  1
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


denominators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
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12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and
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then multiply that result by the numerator of the fraction. The new fractions to be added are
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27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


numerators are added together and the fraction is reduced to the lowest terms.
oo oo oo oo oo oo oo oo oo oo oo oo oo




Format: Multiple oo


Choice Chapter: 1
oo oo oo


Client Needs: Physiological Integrity: Basic Care and Comfort
oo oo oo oo oo oo oo


Cognitive Level: Analyze
oo oo oo


Difficulty: Difficult oo


Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
oo oo oo oo oo oo oo oo


Integrated Process: Communication and Documentation
oo oo oo oo oo


Objective: 1, 2
oo oo oo




4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo



the nurse document as
oo oo oo
WWW.TBSM.WS
consumed?
oo


a. 360
b. 420
c. 510
d. 600
ANS: B o o


Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


number of milliliters consumed, multiply 180  7/3 (
oo oo oo ). When a mixed number is present, oo oo oo oo oo oo oo oo oo oo oo oo



change it to an improper fraction by multiplying the whole number by the denominator and
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


then adding that total to the numerator: 2  3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420
oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo oo


mL (180 ÷ 3 = 60 × 7 = 420).
oo oo oo oo oo oo oo oo oo oo




Format: Multiple oo


Choice Chapter: 1
oo oo oo


Client Needs: Physiological Integrity: Basic Care and Comfort
oo oo oo oo oo oo oo


Cognitive Level: Analyze
oo oo oo


Difficulty: Difficult oo


Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
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Integrated Process: Communication and Documentation
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Objective: 1, 2
oo oo oo




5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms
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were gained since admission?
oo oo oo oo


a. 0.78
b. 0.88

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