,
,Chapter 1: Arithmetic Needed for Dosage
ff ff ff ff ff
MULTIPLE CHOICE ff
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15 oz.
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
What portion of the water remained?
ff ff ff ff ff ff
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A f f
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
fractions, find the largest number that can be divided evenly into the numerator and the denominator
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Apply
ff ff ff
Difficulty: Moderate ff
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Teaching/Learning
ff ff ff
Objective: 1, 2 ff ff
2. A patient/client was prescribed 240 W
ff mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 100 ff ff ff ff ff ff ff ff ff ff ff
mL. What portion of the Ensure remained?
ff ff ff ff ff ff ff
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B f f
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available
ff ff ff ff ff ff ff ff ff ff ff ff ff ff
quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the numerator
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
reduced to its lowest terms of 7/12.
ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Apply
ff ff ff
Difficulty: Moderate ff
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Teaching/Learning
ff ff ff
Objective: 1, 2 ff ff
1|Page
ff ff ff ff ff
, 3. A patient/client consumed
ff oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. What ff f f f f ff ff ff ff ff ff ff ff f f f f ff ff ff ff
is the total number of ounces consumed that should be documented for the patient/client?
ff ff ff ff ff ff ff ff ff ff ff ff ff ff
a. 3 3/4 ff
b. 4 5/12 ff
c. 4 2/3 ff
d. 4 4/9 ff
ANS: B f f
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
multiplying the whole number by the denominator and then adding that total to the numerator. For the
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
the least common denominator (LCD). For 2, 3, and 4, the LCD =
ff ff ff ff ff ff ff ff ff ff ff ff ff
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee),
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
together and the fraction is reduced to the lowest terms.
ff ff ff ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Analyze
ff ff ff
Difficulty: Difficult ff
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Communication and Documentation
ff ff ff ff ff
Objective: 1, 2
ff ff ff
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
the nurse document as consumed?
ff ff ff ff
WWW.TBSM.WS
a. 360
b. 420
c. 510
d. 600
ANS: B f f
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
milliliters consumed, multiply 180 7/3 (
ff ). When a mixed number is present, change it to an
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
improper fraction by multiplying the whole number by the denominator and then adding that total to the
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Analyze
ff ff ff
Difficulty: Difficult ff
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Communication and Documentation
ff ff ff ff ff
Objective: 1, 2
ff ff ff
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
gained since admission?
ff ff ff
a. 0.78
b. 0.88
2|Page
ff ff ff ff ff
,Chapter 1: Arithmetic Needed for Dosage
ff ff ff ff ff
MULTIPLE CHOICE ff
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15 oz.
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
What portion of the water remained?
ff ff ff ff ff ff
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A f f
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
fractions, find the largest number that can be divided evenly into the numerator and the denominator
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Apply
ff ff ff
Difficulty: Moderate ff
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Teaching/Learning
ff ff ff
Objective: 1, 2 ff ff
2. A patient/client was prescribed 240 W
ff mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only 100 ff ff ff ff ff ff ff ff ff ff ff
mL. What portion of the Ensure remained?
ff ff ff ff ff ff ff
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B f f
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available
ff ff ff ff ff ff ff ff ff ff ff ff ff ff
quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the numerator
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
reduced to its lowest terms of 7/12.
ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Apply
ff ff ff
Difficulty: Moderate ff
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Teaching/Learning
ff ff ff
Objective: 1, 2 ff ff
1|Page
ff ff ff ff ff
, 3. A patient/client consumed
ff oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. What ff f f f f ff ff ff ff ff ff ff ff f f f f ff ff ff ff
is the total number of ounces consumed that should be documented for the patient/client?
ff ff ff ff ff ff ff ff ff ff ff ff ff ff
a. 3 3/4 ff
b. 4 5/12 ff
c. 4 2/3 ff
d. 4 4/9 ff
ANS: B f f
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
multiplying the whole number by the denominator and then adding that total to the numerator. For the
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
the least common denominator (LCD). For 2, 3, and 4, the LCD =
ff ff ff ff ff ff ff ff ff ff ff ff ff
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee),
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
together and the fraction is reduced to the lowest terms.
ff ff ff ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Analyze
ff ff ff
Difficulty: Difficult ff
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Communication and Documentation
ff ff ff ff ff
Objective: 1, 2
ff ff ff
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
the nurse document as consumed?
ff ff ff ff
WWW.TBSM.WS
a. 360
b. 420
c. 510
d. 600
ANS: B f f
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
milliliters consumed, multiply 180 7/3 (
ff ). When a mixed number is present, change it to an
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
improper fraction by multiplying the whole number by the denominator and then adding that total to the
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
Format: Multiple Choice f f
Chapter: 1
ff ff
Client Needs: Physiological Integrity: Basic Care and Comfort
ff ff ff ff ff ff ff
Cognitive Level: Analyze
ff ff ff
Difficulty: Difficult ff
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
ff ff ff ff ff ff ff ff
Integrated Process: Communication and Documentation
ff ff ff ff ff
Objective: 1, 2
ff ff ff
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were
ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff
gained since admission?
ff ff ff
a. 0.78
b. 0.88
2|Page
ff ff ff ff ff
