Test Bank
Introductory Mathematical Analysis for Business, Economics, and the Life and
Social Sciences
Author: Ernest F Haeussler
14th Edition
, Table of Contents
Chapter 0 1
Chapter 1 35
Chapter 2 54
Chapter 3 89
Chapter 4 132
Chapter 5 160
Chapter 6 177
Chapter 7 231
Chapter 8 295
Chapter 9 333
Chapter 10 357
Chapter 11 378
Chapter 12 423
Chapter 13 469
Chapter 14 539
Chapter 15 614
Chapter 16 658
Chapter 17 670
,
, Chapter 0
Problems 0.1 x+2 x 2 x
7. True; = + = +1.
2 2 2 2
1. True; –13 is a negative integer.
b ab
2. True, because −2 and 7 are integers and 7 ≠ 0. 8. True, because a = .
c c
3. False, because the natural numbers are 1, 2, 3,
and so on. 9. False; the left side is 5xy, but the right side is
5x2 y.
0
4. False, because 0 = .
1 10. True; by the associative and commutative
properties, x(4y) = (x 4)y = (4 x)y =
5
5. True, because 5 = . 4xy.
1
11. distributive
6. False, SINCE a rational number cannot
have 12. commutative
7
denominator of zero. In fact, is not a number 13. associative
0
at all because we cannot divide by 0. 14. definition of division
7. False, because 25 = 5, which is a positive 15. commutative and distributive
integer.
16. associative
8. True; 2 is an irrational real number.
17. definition of subtraction
9. False; we cannot divide by 0.
18. commutative
10. False, because the natural numbers are 1, 2, 3,
19. distributive
and so on, and 3 lies between 1 and 2.
20. distributive
11. True
21. 2x(y − 7) = (2x)y − (2x)7 = 2xy − (7)(2x)
12. False, SINCE the integer 0 is neither positive = 2xy − (7 · 2)x = 2xy − 14x
nor negative.
22. (a − b) + c = [a + (−b)] + c = a + (−b + c)
Problems 0.2
= a + [c + (−b)] = a + (c − b)
1. False, because 0 does not have a reciprocal. 23. (x + y)(2) = 2(x + y) = 2x + 2y
7 3 21
2. True, because = = 1. 24. 2[27 + (x + y)] = 2[27 + (y + x)] = 2[(27 + y) + x]
3 7 21 = 2[(y + 27) + x]
3. False; the negative of 7 is −7 because 25. x[(2y + 1) + 3] = x[2y + (1 + 3)] = x[2y + 4]
7 + (−7) = 0. = x(2y) + x(4) = (x · 2)y + 4x = (2x)y + 4x
= 2xy + 4x
4. False; 2(3 · 4) = 2(12) = 24, but
(2 · 3)(2 · 4) = 6 · 8 = 48. 26. (1 + a)(b + c) = 1(b + c) + a(b + c)
= 1(b) + 1(c) + a(b) + a(c) = b + c + ab + ac
5. False; –x + y = y + (–x) = y – x.
6. True; (x + 2)(4) = (x)(4) + (2)(4) = 4x + 8.
1
Introductory Mathematical Analysis for Business, Economics, and the Life and
Social Sciences
Author: Ernest F Haeussler
14th Edition
, Table of Contents
Chapter 0 1
Chapter 1 35
Chapter 2 54
Chapter 3 89
Chapter 4 132
Chapter 5 160
Chapter 6 177
Chapter 7 231
Chapter 8 295
Chapter 9 333
Chapter 10 357
Chapter 11 378
Chapter 12 423
Chapter 13 469
Chapter 14 539
Chapter 15 614
Chapter 16 658
Chapter 17 670
,
, Chapter 0
Problems 0.1 x+2 x 2 x
7. True; = + = +1.
2 2 2 2
1. True; –13 is a negative integer.
b ab
2. True, because −2 and 7 are integers and 7 ≠ 0. 8. True, because a = .
c c
3. False, because the natural numbers are 1, 2, 3,
and so on. 9. False; the left side is 5xy, but the right side is
5x2 y.
0
4. False, because 0 = .
1 10. True; by the associative and commutative
properties, x(4y) = (x 4)y = (4 x)y =
5
5. True, because 5 = . 4xy.
1
11. distributive
6. False, SINCE a rational number cannot
have 12. commutative
7
denominator of zero. In fact, is not a number 13. associative
0
at all because we cannot divide by 0. 14. definition of division
7. False, because 25 = 5, which is a positive 15. commutative and distributive
integer.
16. associative
8. True; 2 is an irrational real number.
17. definition of subtraction
9. False; we cannot divide by 0.
18. commutative
10. False, because the natural numbers are 1, 2, 3,
19. distributive
and so on, and 3 lies between 1 and 2.
20. distributive
11. True
21. 2x(y − 7) = (2x)y − (2x)7 = 2xy − (7)(2x)
12. False, SINCE the integer 0 is neither positive = 2xy − (7 · 2)x = 2xy − 14x
nor negative.
22. (a − b) + c = [a + (−b)] + c = a + (−b + c)
Problems 0.2
= a + [c + (−b)] = a + (c − b)
1. False, because 0 does not have a reciprocal. 23. (x + y)(2) = 2(x + y) = 2x + 2y
7 3 21
2. True, because = = 1. 24. 2[27 + (x + y)] = 2[27 + (y + x)] = 2[(27 + y) + x]
3 7 21 = 2[(y + 27) + x]
3. False; the negative of 7 is −7 because 25. x[(2y + 1) + 3] = x[2y + (1 + 3)] = x[2y + 4]
7 + (−7) = 0. = x(2y) + x(4) = (x · 2)y + 4x = (2x)y + 4x
= 2xy + 4x
4. False; 2(3 · 4) = 2(12) = 24, but
(2 · 3)(2 · 4) = 6 · 8 = 48. 26. (1 + a)(b + c) = 1(b + c) + a(b + c)
= 1(b) + 1(c) + a(b) + a(c) = b + c + ab + ac
5. False; –x + y = y + (–x) = y – x.
6. True; (x + 2)(4) = (x)(4) + (2)(4) = 4x + 8.
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