c n
, SOLUTIONS MANUAL cn
to accompany
cn
ORBITAL MECHANICS FOR ENGINEERING STUDENTS
cn cn cn cn
Howard D. Curtis
cn cn
Embry-
Riddle Aeronautical University Daytona Be
cn cn cn cn
ach, Florida
cn
, Solutions Manual c n Orbital Mechanics for Engineering Student cn cn cn cn Chapter 1 cn
s
Problem 1.1 cn
(a)
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A A Axiˆ Ayˆj Azkˆ Axiˆ Ayˆj Azkˆ cn
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Axiˆ Axiˆ Ayˆj Azkˆ Ayˆj Axiˆ Ayˆj Azkˆ Azkˆ Axiˆ Ayˆj Azkˆ
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Ax2 iˆ iˆ Ax Ay iˆ ˆj Ax Az iˆ kˆ Ay Ax ˆj iˆ Ay2 ˆj ˆj Ay Az ˆj kˆ
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2 ˆ ˆ
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Ax2 1 Ax Ay 0 Ax Az 0 Ay Ax 0 Ay2 1 Ay Az 0 Az Ax 0 AzAy 0 Az2 1
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Ax2 Ay2 Az2
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But, according to the Pythagorean Theorem, Ax 2 yA 2 z A 2 A2 , where A A , the magnitude of
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the vector A . Thus A A A .
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(b)
iˆ ˆj kˆ
A B C A Bx
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Ax ByCz BzCy Ay BxCz BzCx Az BxCy ByCx cn
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or
A B C AxByCz AyBzCx AzBxCy AxBzCy AyBxCz AzByCx
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(1) c
Note that A B C C A B , and according to (1)
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C A B CxAyBz Cy AzBx Cz AxBy CxAzBy Cy AxBz Cz AyBx
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(2) c
The right hand sides of (1) and (2) are identical. Hence A B C A B C .
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(c)
iˆ ˆj kˆ iˆ ˆj kˆ
A B C Axiˆ Ayˆj Azkˆ Bx
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A B C B C A B C B C kˆ
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z x x y y z x x y y
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1
, Solutions Manual
c n Orbital Mechanics for Engineering Student
cn cn cn cn Chapter 1
cn
s
Add and subtract the underlined terms to get
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2
, SOLUTIONS MANUAL cn
to accompany
cn
ORBITAL MECHANICS FOR ENGINEERING STUDENTS
cn cn cn cn
Howard D. Curtis
cn cn
Embry-
Riddle Aeronautical University Daytona Be
cn cn cn cn
ach, Florida
cn
, Solutions Manual c n Orbital Mechanics for Engineering Student cn cn cn cn Chapter 1 cn
s
Problem 1.1 cn
(a)
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A A Axiˆ Ayˆj Azkˆ Axiˆ Ayˆj Azkˆ cn
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Axiˆ Axiˆ Ayˆj Azkˆ Ayˆj Axiˆ Ayˆj Azkˆ Azkˆ Axiˆ Ayˆj Azkˆ
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Ax2 iˆ iˆ Ax Ay iˆ ˆj Ax Az iˆ kˆ Ay Ax ˆj iˆ Ay2 ˆj ˆj Ay Az ˆj kˆ
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Ax2 1 Ax Ay 0 Ax Az 0 Ay Ax 0 Ay2 1 Ay Az 0 Az Ax 0 AzAy 0 Az2 1
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Ax2 Ay2 Az2
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But, according to the Pythagorean Theorem, Ax 2 yA 2 z A 2 A2 , where A A , the magnitude of
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the vector A . Thus A A A .
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(b)
iˆ ˆj kˆ
A B C A Bx
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Ax ByCz BzCy Ay BxCz BzCx Az BxCy ByCx cn
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or
A B C AxByCz AyBzCx AzBxCy AxBzCy AyBxCz AzByCx
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(1) c
Note that A B C C A B , and according to (1)
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C A B CxAyBz Cy AzBx Cz AxBy CxAzBy Cy AxBz Cz AyBx
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(2) c
The right hand sides of (1) and (2) are identical. Hence A B C A B C .
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(c)
iˆ ˆj kˆ iˆ ˆj kˆ
A B C Axiˆ Ayˆj Azkˆ Bx
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z x x y y z x x y y
B A C A C C A B A B kˆ cn cn cn cn
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1
, Solutions Manual
c n Orbital Mechanics for Engineering Student
cn cn cn cn Chapter 1
cn
s
Add and subtract the underlined terms to get
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2