OPM1501 Orientation to Intermediate Phase Mathematics (OPM1501)

University of South Africa

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OPM1501 Assignment 3 Due 15 July 2022 (Answers)

OPM1501 Assignment 3 Due 15 July 2022 (Answers)
Exam (elaborations) • 15 pages • 2022

PART A 1. 0 0 1 ×3 -4 1 2 2 k 3 K = 3 Therefore 3×3 = 9 9-4 = 5 2. Input value 0 1 2 k Output value 0 -1 2 5 3. 0, 3 , 8 , 15 , 24 , 35 , 48 , 63 , 80 , 99, 120 3 5 7 9 11 13 15 17 19 20 2 2 2 2 2 2 2 2 2 Therefore, the eleventh for this sequence is 12 4. (i) 5 6 7 12 13 14 19 20 21 1 (ii) 7 8 10 14 15 16 2 2 1 2 3 (iii) 8 9 10 15 16 17 (iv) 2 3 4 9 10 11 16 17 18 5. Yes 6 + 14 + 12 + 20 = 52 6. YES Of 19 Same at the right-hand side 13 + 7...