DSC1630
ASSIGNMENT 2 SEMESTER 2 2025
UNIQUE NO.
DUE DATE: SEPTEMBER 2025
, Question 1
Problem: Determine the equivalent weekly compounded interest rate (to two decimal
places) of an interest rate of 14.90% per year, compounded quarterly.
Solution (steps):
1. Quarterly nominal rate (per quarter):
0.1490
𝑗𝑞 = = 0.03725
4
2. Find the effective annual rate (EAR) generated by 14.90% p.a. compounded
quarterly:
EAR = (1 + 𝑗𝑞 )4 − 1 = (1 + 0.03725) 4 − 1
Numerically,
EAR ≈ 0.1575340471 (i.e. 15.75340471%)
3. Let the nominal weekly rate (convert to percentage p.a., compounded weekly) be
𝑖week,nom . Weekly compounding has 52 periods per year. We require
(1 + 𝑖week,nom ⁄52)52 = 1 + EAR
So
𝑖week,nom ⁄52 = (1 + EAR)1/52 − 1
and
𝑖week,nom = 52((1 + EAR)1/52 − 1).
4. Compute:
𝑖week,nom ≈ 0.1464978960 (decimal) = 14.64978960% p.a.
Answer (rounded to two decimal places): 14.65% p.a. (nominal, compounded
weekly).
ASSIGNMENT 2 SEMESTER 2 2025
UNIQUE NO.
DUE DATE: SEPTEMBER 2025
, Question 1
Problem: Determine the equivalent weekly compounded interest rate (to two decimal
places) of an interest rate of 14.90% per year, compounded quarterly.
Solution (steps):
1. Quarterly nominal rate (per quarter):
0.1490
𝑗𝑞 = = 0.03725
4
2. Find the effective annual rate (EAR) generated by 14.90% p.a. compounded
quarterly:
EAR = (1 + 𝑗𝑞 )4 − 1 = (1 + 0.03725) 4 − 1
Numerically,
EAR ≈ 0.1575340471 (i.e. 15.75340471%)
3. Let the nominal weekly rate (convert to percentage p.a., compounded weekly) be
𝑖week,nom . Weekly compounding has 52 periods per year. We require
(1 + 𝑖week,nom ⁄52)52 = 1 + EAR
So
𝑖week,nom ⁄52 = (1 + EAR)1/52 − 1
and
𝑖week,nom = 52((1 + EAR)1/52 − 1).
4. Compute:
𝑖week,nom ≈ 0.1464978960 (decimal) = 14.64978960% p.a.
Answer (rounded to two decimal places): 14.65% p.a. (nominal, compounded
weekly).