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MAT3705 ASSIGNMENT 4 2025 *SOLUTIONS & CALCULATIONS * DUE DATE 11 SEPTEMBER 2025 (BEST ANSWERS FOR THIS ASSIGNMENT)

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MAT3705 ASSIGNMENT 4 2025 *SOLUTIONS & CALCULATIONS * DUE DATE 11 SEPTEMBER 2025 (BEST ANSWERS FOR THIS ASSIGNMENT)










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Uploaded on
September 9, 2025
Number of pages
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Written in
2025/2026
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Exam (elaborations)
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, MAT3705 ASSIGNMENT 4 2025 SOLUTIONS
DUE DATE: 11 SEPTEMBER 2025



Question 1

Let

𝟏
(𝒇(𝒛) = )
𝐬𝐢𝐧(𝟏/𝒛)



(a) What type of singularity is ( 𝒛 = 𝟎 )? Provide reasons for your answer.

Solution:

• Zeros of sin(𝑤 ) occur when 𝑤 = 𝑛𝜋, 𝑛 ∈ 𝑍.
• For 𝑓 (𝑧), zeros of the denominator happen when

𝑧1 = 𝑛𝜋 ⟹ 𝑧 = 𝑛𝜋1
1 1 1
• Hence 𝑓 (𝑧) has poles at 𝑧 = , , , … , which accumulate at 𝑧 = 0.
π 2π 3π

• Therefore, 𝑧 = 0 is not an isolated singularity but an essential singularity.

𝒛 = 𝟎 is an essential singularity (non-isolated).



𝟏
(b) What type of singularity is 𝒛 = ? Provide reasons for your answer.
𝟐𝜋

Solution:

1
• At 𝑧 = :
2𝜋


sin(𝑧1 ) = sin(2𝜋) = 0.

• Near this point, expand:

sin(𝑧1 ) ≈ 𝑧1 − 2𝜋.

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