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Exam (elaborations)

StraighterLine Exam 2 questions and answers

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StraighterLine Exam 2 questions and answers questions and answers questions and answers

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StraighterLine Exam 2 (Chpt. 4-6)

b. Rb2CrO4 - Which of the following is soluble in water?



a. AgCl

b. Rb2CrO4

c. Hg2I2

d. CaSO4

e. PbBr2



c. BaSO4 will precipitate; Cu2+ and Cl- are spectator ions. - Based on the solubility rules, which of these
processes will occur if solutions of CuSO4(aq) and BaCl2(aq) are mixed?



Select one:

a. CuCl2 will precipitate; Ba2+ and SO42- are spectator ions.

b. CuSO4 will precipitate; Ba2+ and Cl- are spectator ions.

c. BaSO4 will precipitate; Cu2+ and Cl- are spectator ions.

d. BaCl2 will precipitate; Cu2+ and SO42- are spectator ions.

e. No precipitate will form.



c. H+(aq) + OH-(aq) → H2O(l) - Which is the net ionic equation for the reaction between aqueous
solutions of lithium hydroxide and hydrobromic acid?LiOH(aq) + HBr(aq) → H2O(l) + LiBr(aq)



Select one:

a. LiOH(aq) → Li+(aq) + OH-(aq)

b. HBr(aq) → H+(aq) + Br-(aq)

c. H+(aq) + OH-(aq) → H2O(l)

d. Li+(aq) + Br-(aq) → LiBr(aq)

, e. Li+(aq) + OH-(aq)+ H+(aq) + Br-(aq) → H2O(l) + LiBr(aq)



d. CaCl2 - Which salt is formed in the neutralization reaction of hydrochloric acid with calcium
hydroxide?



Select one:

a. CaO

b. CaCl

c. CaH2

d. CaCl2

e. NaCl



d. AgBr - Based on the solubility rules, which one of these compounds is insoluble in water?



Select one:

a. NaCl

b. MgBr2

c. FeCl2

d. AgBr

e. ZnCl2



b. MnO4- - What is the oxidizing agent in the following reaction?5Fe2+(aq) + MnO4-(aq) + 8H+(aq) →
5Fe3+(aq) + Mn2+(aq) + 4H2O(l)



Select one:

a. Fe2+

b. MnO4-

c. H+

d. Mn2+
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