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MIP1502 Assignment 4 (COMPLETE ANSWERS) 2025 (721016) - DUE 15 August 2025

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MIP1502 Assignment 4 (COMPLETE ANSWERS) 2025 (721016) - DUE 15 August 2025 Question 1 This question requires you to move beyond simply solving mathematical problems. You will analyse functional relationships, diagnose a common learner misconception based on the principles in your learning material, and design a learning activity that aligns with the CAPS curriculum for the Intermediate Phase. 1.1 Consider the two real-world situations below. The first represents a linear function, and the second represents a non-linear function. • Situation 1 (Linear): A rental van costs R230 per day plus R4,30 per kilometre driven. • Situation 2 (Non-linear): The area of a circle depends on the length of its radius. For each situation, you must: 1.1.1 Identify the independent variable (input) and the dependent variable (output). (2) 1.1.2 Write a function rule using function notation (e.g.,

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,MIP1502 Assignment 4 (COMPLETE
ANSWERS) 2025 (721016) - DUE 15 August
2025
MIP1502 FULL ASSIGNMENT RESPONSE


Question 1 (20 marks)
1.1 Functional Relationships
Situation 1 (Linear):
 Cost = R230 per day + R4.30 per km driven
1.1.1 Independent and Dependent Variables
 Independent Variable: Number of kilometres driven
 Dependent Variable: Total cost of the rental
1.1.2 Function Rule (Linear)
Let the number of kilometres be xx, and cost be f(x)f(x):
f(x)=230+4.30xf(x) = 230 + 4.30x
1.1.3 Table of Values
Kilometres (x) Cost (R)
0 230
50 230 + 215 = 445
100 230 + 430 = 660

, Kilometres (x) Cost (R)
150 230 + 645 = 875
1.1.4 Graph Sketch (Description)
 X-axis: Kilometres driven
 Y-axis: Total cost
 Straight line starting at (0, 230) with constant slope
(gradient) of 4.30


Situation 2 (Non-linear):
 Area of circle depends on radius
1.1.1 Independent and Dependent Variables
 Independent Variable: Radius
 Dependent Variable: Area
1.1.2 Function Rule (Non-linear)
Let radius be rr, and area be A(r)A(r):
A(r)=πr2A(r) = \pi r^2
1.1.3 Table of Values
Radius (r) Area (A=πr2A = \pi r^2)
1 3.14
2 12.57

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