, Question 1
5
3 as an improper fraction
6
(3×6)+5
= 6
18+5
= 6
23
= 6
Option [2]
Question 2
29
as a mixed fraction
8
𝑑𝑖𝑣𝑖𝑑𝑒 29 𝑏𝑦 8 𝑡𝑜 𝑔𝑒𝑡 3 𝑟𝑒𝑚𝑎𝑖𝑛𝑑𝑒𝑟 5
5
= 38
Option [3]
Question 3
4𝑎𝑏 ; 6𝑎2 𝑏 2 ; 14𝑎2 𝑏3
𝐿𝑜𝑤𝑒𝑠𝑡 𝑐𝑜𝑚𝑚𝑜𝑛 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑒 𝐿𝐶𝑀
𝐿𝐶𝑀 𝑜𝑓 4; 6 ; 14 𝑖𝑠 84
ℎ𝑖𝑔ℎ𝑒𝑠𝑡 𝑝𝑜𝑤𝑒𝑟 𝑜𝑓 𝑎 𝑖𝑠 2
ℎ𝑖𝑔ℎ𝑒𝑠𝑡 𝑝𝑜𝑤𝑒𝑟 𝑜𝑓 𝑏 𝑖𝑠 3
therefore LCM is 84𝑎2 𝑏3
Option [3]
Question 4
7𝑠 2 ; 2𝑠𝑡 ; 4𝑡 2
𝐿𝑜𝑤𝑒𝑠𝑡 𝑐𝑜𝑚𝑚𝑜𝑛 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑒 𝐿𝐶𝑀
𝐿𝐶𝑀 𝑜𝑓 7 ; 2 ; 4 𝑖𝑠 28
ℎ𝑖𝑔ℎ𝑒𝑠𝑡 𝑝𝑜𝑤𝑒𝑟 𝑜𝑓 𝑠 𝑖𝑠 2
ℎ𝑖𝑔ℎ𝑒𝑠𝑡 𝑝𝑜𝑤𝑒𝑟 𝑜𝑓 𝑡 𝑖𝑠 2
therefore LCM is 28𝑡 2
Option [2]
Question 5
2(𝑥𝑦)2
8𝑥 3
