Structural Analysis IV
Project Solutions
2024
0027 65 934 4052
,TABLE OF CONTENTS
1.0 INTRODUCTION .......................................................................................................... 3
2.0 SCOPE OF THE PROJECT ........................................................................................... 3
3.0 ANALYSIS OF STRUCTURAL ELEMENTS AND RESULTS ................................. 6
,1.0 INTRODUCTION
Structural analysis and design is important as it focuses on the critical parts that need special
attention. Loads act on a structure in different directions. In structural design, worst case
loading conditions which result into the highest stresses are used to analyse a structure. Parts
of the structure that experience high Von –Mises stress or high buckling are isolated for further
analysis.
Engineering principles mainly used in this analysis derives knowledge from the following
topics:
Statics
Strength of materials
Machine elements
Material selection
2.0 SCOPE OF THE PROJECT
The project focuses on structural analysis of various structural elements using relevant
software tools and engineering principles. The following questions will be answered:
,
,
, 3.0 ANALYSIS OF STRUCTURAL ELEMENTS AND RESULTS
A1
Damping factor calculations
Load from the fluid9.8 kN
Height of wall 22.5 m
Tank diameter 100 m
Thickness of wall 0.8 m
Poisson's ratio 0
finite beam
ANALYSIS FOR FINITE BEAM CASE
Step 1
Calculations for µ
µ= 0.20808957
µL= 4.68201538
Step 2
Based on the boundary conditions at x = 0, the bending moment M = 0 and the equation 5.5 SG can be simplified to (A1-B1=0).
This is equation 01 for the matrix formation
Based on the boundary conditions at x = 0, the shear force V = 0 and the equation 5.6 SG can be simplified to (-A1-A2-B1+B2=0).
This is equation 02 for the matrix formation
From equation 5.3 SG the deflection distribution is given. It can be calculated from the coefficients for A1, A2, B1, and B2. These
coefficients will form part of the equation 03 for the matrix formation .
Calculation for coefficient equation 03
Coefficient A1= -0.00925606
Coefficient A2= -0.00028123 4E µ^4v-q= -220.5
Coefficient B1= -107.93768101
Coefficient B2= -3.27946438
From equation 5.4 SG the slope distribution is given. It can be calculated from the coefficients for A1, A2, B1, and B2. These
coefficients will form part of the equation 04 for the matrix formation.
Calculation for coefficient equation 04
Coefficient A1= 0.0089748343
Coefficient A2= 0.0095372871 4EI µ^3(dq/dx)-1/µ(dq/dx)= -47.09510372
Coefficient B1= -111.2171453858
Coefficient B2= 104.6582166307
Project Solutions
2024
0027 65 934 4052
,TABLE OF CONTENTS
1.0 INTRODUCTION .......................................................................................................... 3
2.0 SCOPE OF THE PROJECT ........................................................................................... 3
3.0 ANALYSIS OF STRUCTURAL ELEMENTS AND RESULTS ................................. 6
,1.0 INTRODUCTION
Structural analysis and design is important as it focuses on the critical parts that need special
attention. Loads act on a structure in different directions. In structural design, worst case
loading conditions which result into the highest stresses are used to analyse a structure. Parts
of the structure that experience high Von –Mises stress or high buckling are isolated for further
analysis.
Engineering principles mainly used in this analysis derives knowledge from the following
topics:
Statics
Strength of materials
Machine elements
Material selection
2.0 SCOPE OF THE PROJECT
The project focuses on structural analysis of various structural elements using relevant
software tools and engineering principles. The following questions will be answered:
,
,
, 3.0 ANALYSIS OF STRUCTURAL ELEMENTS AND RESULTS
A1
Damping factor calculations
Load from the fluid9.8 kN
Height of wall 22.5 m
Tank diameter 100 m
Thickness of wall 0.8 m
Poisson's ratio 0
finite beam
ANALYSIS FOR FINITE BEAM CASE
Step 1
Calculations for µ
µ= 0.20808957
µL= 4.68201538
Step 2
Based on the boundary conditions at x = 0, the bending moment M = 0 and the equation 5.5 SG can be simplified to (A1-B1=0).
This is equation 01 for the matrix formation
Based on the boundary conditions at x = 0, the shear force V = 0 and the equation 5.6 SG can be simplified to (-A1-A2-B1+B2=0).
This is equation 02 for the matrix formation
From equation 5.3 SG the deflection distribution is given. It can be calculated from the coefficients for A1, A2, B1, and B2. These
coefficients will form part of the equation 03 for the matrix formation .
Calculation for coefficient equation 03
Coefficient A1= -0.00925606
Coefficient A2= -0.00028123 4E µ^4v-q= -220.5
Coefficient B1= -107.93768101
Coefficient B2= -3.27946438
From equation 5.4 SG the slope distribution is given. It can be calculated from the coefficients for A1, A2, B1, and B2. These
coefficients will form part of the equation 04 for the matrix formation.
Calculation for coefficient equation 04
Coefficient A1= 0.0089748343
Coefficient A2= 0.0095372871 4EI µ^3(dq/dx)-1/µ(dq/dx)= -47.09510372
Coefficient B1= -111.2171453858
Coefficient B2= 104.6582166307
