EPE3701 power engineering systems Assig 1 2024

2024





POWER ENGINEREERING
SYSYTEM (EPE 3701)




JNY-LX1
EPE3701 Power Engineering Systems
Welcome to the EPE3701 assessment
1/minor test 1. Date: 2024-03-25 Time:
08:00 Hours: Examiner name: TS Hlalele
External moderator name: PT Manditereza
This paper consists of 3 pages including
cover page. Total marks: 42 due
09/APRIL/2024 11:pm
4/9/2024

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QUESTION 1

[22] A three-phase synchronous generator with negligible armature resistance
has synchronous reactance Xs = 1.65 p.u. and is connected to a very large
system. The terminal voltage is 1.0 p.u. and the generator is supplying to the
system a current of 0.9 p.u. at 0.85 p.f. (lag). Determine: 1.1 The magnitude
and angle of the internal voltage, E; (4)



To determine the magnitude and angle of the internal voltage, E, we can use the
equation:

E = V + I*Xs



Where:

V = terminal voltage = 1.0 p.u.

I = current supplied to the system = 0.9 p.u. at 0.85 p.f. (lag)

Xs = synchronous reactance = 1.65 p.u.



First, we need to convert the current to its rectangular form:

I = 0.9 ∠ -31.8 degrees