MAT1512
Assignment 3
(592899)
Due date: 4 August 2023
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,(a)
x 2 + y2 = 4
dy
2x + 2y = 0
dx
dy −2x
=
dx 2y
dy x
= −
dx y
(b)
7y2 + sin(3x) = 12 – y4
dy
14y + cos(3x)(3) = 12 – y4
dx
dy dy
14y + 4y3 = -3cos(3x)
dx dx
dy
(14y + 4y3) = -3cos(3x)
dx
dy dy−3cos3x
=
dx 14y+4y^3
, (c)
(d)
tan(x2y4) = 3x + y2
dy dy
sec2(x2y2). (x2y4) = 3 + 2y
dx dx
dy dy
sec2(x2y2)(2xy4 + x2.4y 3 ) -2y = 3
dx dx
dy dy
2xy4sec2(x2y4) + 4x2y3sec2(x2y4) -2y = 3
dx dx
dy dy
4x2y3sec2(x2y4) – 2y = 3 -2xy4.sec2(x2y4)
dx dx
dy (3 −2𝑥𝑦^4.𝑠𝑒𝑐 ^2(𝑥^2𝑦^4))
=
dx (4𝑥^2𝑦^3𝑠𝑒𝑐 ^2(𝑥^(2𝑦^4 ))−2𝑦)
(e)
4x2y7 – 2x = x5 + 4y3
4x2y7 – 4y3 = x5 + 2x
dy dy
8xy7 + 4x2(7y) – 12y2 = 5x4 + 2
dx dx
dy
(28x2y -12y2) = -8xy7 + 5x4 + 2
dx
dy −8𝑥𝑦 7 +5𝑥 4 +2
=
dx 28𝑥 2 𝑦−12𝑦 2