MAT1511
ASSIGNMENT 4
2022
, Solution:
i).
5 −2 𝑥 𝑦 2 −1
[ ]+[ ]=[ ]
−4 3 𝑤 𝑧 3 6
5+𝑥 −2 + 𝑦 2 −1
[ ]=[ ]
−4 + 𝑤 3+𝑧 3 6
5+𝑥 =2 1
𝑥 =2−5
𝑥 = −3
−2 + 𝑦 = −1 2
𝑦 = −1 + 2
𝑦=1
−4 + 𝑤 = 3 3
𝑤 =3+4
𝑤=7
3+𝑧 =6 4
𝑧 =6−3
𝑧=3
ASSIGNMENT 4
2022
, Solution:
i).
5 −2 𝑥 𝑦 2 −1
[ ]+[ ]=[ ]
−4 3 𝑤 𝑧 3 6
5+𝑥 −2 + 𝑦 2 −1
[ ]=[ ]
−4 + 𝑤 3+𝑧 3 6
5+𝑥 =2 1
𝑥 =2−5
𝑥 = −3
−2 + 𝑦 = −1 2
𝑦 = −1 + 2
𝑦=1
−4 + 𝑤 = 3 3
𝑤 =3+4
𝑤=7
3+𝑧 =6 4
𝑧 =6−3
𝑧=3