100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.2 TrustPilot
logo-home
Exam (elaborations)

chem1012/1013A:complete notes and steps-8DEC2021

Rating
-
Sold
1
Pages
29
Grade
A+
Uploaded on
07-12-2021
Written in
2021/2022

Often students are faced with a blockage in many questions in semester 2 due to the inaccessibility of the set of instructions which ultimately make it easy to comprehend questions. Chemistry is often disguised as a subject that requires much understanding and a lot of memorizing, yet this is not the case for many of the top achievers. Top achievers compress their understanding into a simple set of instructions that they use. Fortunately, this set of instructions are found and explained in this document.

Show more Read less










Whoops! We can’t load your doc right now. Try again or contact support.

Document information

Uploaded on
December 7, 2021
Number of pages
29
Written in
2021/2022
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

Content preview

CHEM 1012A/1013A
By Amatullah Chiosa




Often students are faced with a blockage in many questions in semester 2 due to the
inaccessibility of the set of instructions which ultimately make it easy to comprehend questions.
Chemistry is often disguised as a subject that requires much understanding and a lot of
memorizing, yet this is not the case for many of the top achievers. Top achievers compress their
understanding into a simple set of instructions that they use. Fortunately, this set of instructions
are found and explained in this document.




CONCEPTS COVERED
Chemical kinetics
Chemical equilibrium
Acids and base equilibrium
Aspects of aqueous equilibria
Thermochemistry

, Chemical kinetics
Chemical kinetics- ‘measurement of how quickly reaction occur.’1
Rate of reaction is the change in concentration per unit time.
[𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑐𝑜𝑛𝑐𝑒𝑛𝑡𝑟𝑎𝑡𝑖𝑜𝑛] 𝛥𝑚𝑜𝑙𝑎𝑟𝑖𝑡𝑦
Average rate= 𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑡𝑖𝑚𝑒
= 𝛥𝑡 = M.s-1

Rate law shows the relationship between rate of reaction and concentrations of the reactants.
For the chemical reaction: aA+bB⇌cC+dD
rate law=k[A]m[B]n.
k is the rate constant
m, n are the numbers indicating the reaction order.
The reaction order indicates the relationship between the concentration of species and the rate of
the reaction.

Finding The Reaction Order:
CASE 1:
If the overall reaction order is not given. Use the coefficients of the reactants.
• When rate of reaction is proportional to the concentration of a substance then it is
a first order reaction, meaning power of A is 1. (a unimolecular process- one mol-
ecule involved)
• When rate of reaction is proportional to the A2, then it is a second order reaction.
(a bimolecular process-two molecules involved)
• When rate of reaction is independent of the concentration of A, then the reaction
is a zero-order reaction.
E.g., aA+bB ⇌cC
Rate law= k[A]a[B]b
CASE 2:
If overall reaction order is given.
Overall reaction order= sum of the individual reaction orders.

E.g., aA ⇌Bb + cC
Overall reaction order=2
Rate law=k[A]2
CASE 3: More than 1 rate of reaction is given (this may be in the form of a table).

1
Chemistry: the central science, Brown et al. (Brown et al., no date)

, Then follow this three-step system to find the reaction order which is the power of the
concentration of the reactants
Step 1: if there is more than one reactant, look for the two rows where only one reactant
concentration changes.

e.g.
aA+bB ⇌ 𝑐C

[A] [B] Rate of reaction
0.1 0.3 1.64x10-4
0.1 0.6 1.78x10-4
0.21 0.3 3.2x10-4

Step 2: substitute into this formula
𝑟𝑎𝑡𝑒2 𝑎 𝑏
[0.6] 𝑎 𝑏 [0.6] −4

𝑟𝑎𝑡𝑒1
==𝐾[0.1]
𝑘[0.1]𝑎 [0.3]𝑏
=𝐾[0.1]
𝑘[0.1]𝑎 [0.3]𝑏
=1.78𝑥10
1.64𝑥10−4
⟹ 1.085=2b ⟹ b=log2[1.085]⟹ b= 0.12


Step 3: repeat above process to find a.
𝑟𝑎𝑡𝑒3 𝐾[𝐴]𝑎 [B]𝑏 3.2𝑥10−4 𝐾[0.21]𝑎 [0.3]𝑏
= ⟹ = ⟹ 1.95=2.1b ⟹ b=log2.1[1.95] ⟹ a= 0.9
𝑟𝑎𝑡𝑒1 𝑘[𝐴]𝑎 [𝐵]𝑏 1.64𝑥10−4 𝑘[0.1]𝑎 [0.3]𝑏

Overall reaction order=0.12+0.9=1.02


.

Half-Life: First Order Reaction
The time needed for a reaction to reach half of its original concentration. t1/2 is independ-
ent of concentration.
0.693
t1/2= 𝑘



Collision Theory: Temperature and Rates
Collision literally means for two objects to crash or hit against each other. For this to happen
well enough to cause a reaction; enough molecules must collide at the right kinetic energy. The
more the collisions, the faster the rate. As the kinetic energy increases, so does the speed at
which it occurs, and the rate consequently increases.
In simple terms: average kinetic energy= temperature ∝ reaction rate
R80,00
Get access to the full document:

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached

Get to know the seller
Seller avatar
practisemakesperfect
3,0
(2)

Get to know the seller

Seller avatar
practisemakesperfect University of the Witwatersrand
View profile
Follow You need to be logged in order to follow users or courses
Sold
5
Member since
4 year
Number of followers
4
Documents
10
Last sold
2 year ago
PRACTISE MAKES PROGRESS

3,0

2 reviews

5
0
4
1
3
0
2
1
1
0

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their exams and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can immediately select a different document that better matches what you need.

Pay how you prefer, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card or EFT and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions