STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
C. 1.8 - CORRECT ANSWERS The random variable X, representing the number of
accidents in a certain intersection in a week, has the following probability distribution:
On average, how many accidents are there in the intersection in a week?
A. 5.3
B. 2.5
C. 1.8
D. 0.30
E. 0.1667
Mean = 20.6800 (sum product)
Variance = 1.6376 Sumproduct(x - mean)^2, p(x)
Standard Deviation = 1.2797 (sqrt of variance)
Approximately how many arrangements should the florist expect to deliver each week,
rounded to the nearest whole number? = 145 (20.68 * 7) - CORRECT ANSWERS A florist
determines the probabilities for the number of flower arrangements they deliver each day.
,STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
Find the mean, variance, and standard deviation of the distribution rounded to 4 decimal
places.
Mean =
Variance =
Standard Deviation =
Approximately how many arrangements should the florist expect to deliver each week,
rounded to the nearest whole number?
B. Yes, the probabilities associated with each X are all positive and they all add up to 1. -
CORRECT ANSWERS Determine if the following could be a probability distribution for a
discrete random variable, X. If no, state why.
A. Yes, the values of X are all positive.
B. Yes, the probabilities associated with each X are all positive and they all add up to 1.
C. No, the values of X do not start at 1 and the probabilities do not add up to 1.
D. No, the probabilities do not add up to 1.
All 10 have the disease, rounded to four decimal places? 0.0947 (binom.dist(10,10,.79,0)
,STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
At least 8 have the disease, rounded to four decimal places? .6474 (1-binom.dist(7,10,.79,1)
At most 4 have the disease, rounded to four decimal places? .0082 (binom.dist(4,10,.79,1) -
CORRECT ANSWERS A certain medical test is known to detect 79% of the people who
are afflicted with the disease Y. If 10 people with the disease are administered the test, what is
the probability that the test will show that:
All 10 have the disease, rounded to four decimal places?
At least 8 have the disease, rounded to four decimal places?
At most 4 have the disease, rounded to four decimal places?
(a) .00023 (1-norm.dist(29,22,2,1))
(b) 20.522 (norm.inv(.23,22,2)) - CORRECT ANSWERS The distribution of scores on a
recent test closely followed a Normal Distribution with a mean of 22 points and a standard
deviation of 2 points. For this question, DO NOT apply the standard deviation rule.
(a) What proportion of the students scored at least 29 points on this test, rounded to five
decimal places?
(b) What is the 23 percentile of the distribution of test scores, rounded to three decimal places?
(a) .10919 (norm.dist(6,7.37,3,1) - (norm.dist(5,7.37,3,1)
, STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
(b) .32396 (norm.dist(6.7.37,3,1) - CORRECT ANSWERS A study was made of seat belt
use among children who were involved in car crashes that caused them to be hospitalized. It
was found that children not wearing any restraints had hospital stays with a mean of 7.37 days
and a standard deviation of 3 days with an approximately normal distribution.
(a) Find the probability that their hospital stay is from 5 to 6 days, rounded to five decimal
places.
(b) Find the probability that their hospital stay is greater than 6 days, rounded to five decimal
places.
C. 57.3% and 42.7% are both statistics. - CORRECT ANSWERS In June 2015, Gallup
conducted a poll of a random sample of 14903 adults to determine the well-being of people
living in the United States. One question asked, "Did you exercise at least 30 minutes for 3 or
more days in the past week?" In the survey, 57.3% of males and 42.7% of females responded
yes to this question. Which of the following is true about this scenario?
A. 57.3% and 42.7% are both parameters.
B. If we took another random sample of 14903 adults, we would expect to get the exact same
results.
C. 57.3% and 42.7% are both statistics.
0.87589
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
C. 1.8 - CORRECT ANSWERS The random variable X, representing the number of
accidents in a certain intersection in a week, has the following probability distribution:
On average, how many accidents are there in the intersection in a week?
A. 5.3
B. 2.5
C. 1.8
D. 0.30
E. 0.1667
Mean = 20.6800 (sum product)
Variance = 1.6376 Sumproduct(x - mean)^2, p(x)
Standard Deviation = 1.2797 (sqrt of variance)
Approximately how many arrangements should the florist expect to deliver each week,
rounded to the nearest whole number? = 145 (20.68 * 7) - CORRECT ANSWERS A florist
determines the probabilities for the number of flower arrangements they deliver each day.
,STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
Find the mean, variance, and standard deviation of the distribution rounded to 4 decimal
places.
Mean =
Variance =
Standard Deviation =
Approximately how many arrangements should the florist expect to deliver each week,
rounded to the nearest whole number?
B. Yes, the probabilities associated with each X are all positive and they all add up to 1. -
CORRECT ANSWERS Determine if the following could be a probability distribution for a
discrete random variable, X. If no, state why.
A. Yes, the values of X are all positive.
B. Yes, the probabilities associated with each X are all positive and they all add up to 1.
C. No, the values of X do not start at 1 and the probabilities do not add up to 1.
D. No, the probabilities do not add up to 1.
All 10 have the disease, rounded to four decimal places? 0.0947 (binom.dist(10,10,.79,0)
,STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
At least 8 have the disease, rounded to four decimal places? .6474 (1-binom.dist(7,10,.79,1)
At most 4 have the disease, rounded to four decimal places? .0082 (binom.dist(4,10,.79,1) -
CORRECT ANSWERS A certain medical test is known to detect 79% of the people who
are afflicted with the disease Y. If 10 people with the disease are administered the test, what is
the probability that the test will show that:
All 10 have the disease, rounded to four decimal places?
At least 8 have the disease, rounded to four decimal places?
At most 4 have the disease, rounded to four decimal places?
(a) .00023 (1-norm.dist(29,22,2,1))
(b) 20.522 (norm.inv(.23,22,2)) - CORRECT ANSWERS The distribution of scores on a
recent test closely followed a Normal Distribution with a mean of 22 points and a standard
deviation of 2 points. For this question, DO NOT apply the standard deviation rule.
(a) What proportion of the students scored at least 29 points on this test, rounded to five
decimal places?
(b) What is the 23 percentile of the distribution of test scores, rounded to three decimal places?
(a) .10919 (norm.dist(6,7.37,3,1) - (norm.dist(5,7.37,3,1)
, STATISTICS FINAL EXAM NON-CREDIT TEST REVIEW EXAM
QUESTIONS AND ANSWERS UPDATED 2025/2026 A COMPLETE
SOLUTION ALL ANSWERS GET IT 100% CORRECT DETAILED
BEST GRADED TO SCORE A+ FOR SUCCESS
(b) .32396 (norm.dist(6.7.37,3,1) - CORRECT ANSWERS A study was made of seat belt
use among children who were involved in car crashes that caused them to be hospitalized. It
was found that children not wearing any restraints had hospital stays with a mean of 7.37 days
and a standard deviation of 3 days with an approximately normal distribution.
(a) Find the probability that their hospital stay is from 5 to 6 days, rounded to five decimal
places.
(b) Find the probability that their hospital stay is greater than 6 days, rounded to five decimal
places.
C. 57.3% and 42.7% are both statistics. - CORRECT ANSWERS In June 2015, Gallup
conducted a poll of a random sample of 14903 adults to determine the well-being of people
living in the United States. One question asked, "Did you exercise at least 30 minutes for 3 or
more days in the past week?" In the survey, 57.3% of males and 42.7% of females responded
yes to this question. Which of the following is true about this scenario?
A. 57.3% and 42.7% are both parameters.
B. If we took another random sample of 14903 adults, we would expect to get the exact same
results.
C. 57.3% and 42.7% are both statistics.
0.87589
