BIOLOGY PAPER 1 LATEST ACTUAL EXAM WITH
COMPLETE QUESTIONS AND CORRECT
VERIFIED ANSWERS ALREADY GRADED A+
100% GUARANTEED TO PASS CONCEPTS
◉The movement of Na⁺ out of the cell allows the absorption of glucose
into the cell lining the ileum.
Explain how. . Answer: The sodium ions are pumped into the blood from
epithelial cell, this means there is no NAT left in the epithelial cell.
Therefore, there is a diffusion gradient generated for the sodium ions
from the ileum into cell. The sodium ions that are moving in, by
facilitated diffusion, brings glucose with it.
◉Describe and explain two feature you would expect to find in a cell
specialised for absorption. . Answer: 1) Folded membrane so a large
surface area for absorption.
2) Large number of channel proteins so fast rate of absorption.
◉Figure shows the SGLT1 polypeptide so there is always NH₂ at one
end and COOH at the other end.
Describe how amino acids join to form a polypeptide so there is always
NH₂ at one end and COOH at the other end. . Answer: One amine group
, joins to a carboxyl group to form a peptide bond, so in the chain there is
a free amine group at one end and a free carboxyl group at the other.
Include a diagram ( drawn on paper test)
◉Formation of an enzyme-substrate complex increases the rate of
reaction.
Explain how.
2 marks . Answer: The formation of an enzyme-substrate complex
causes a reduction in the activation energy that is used for the reaction to
take place by bending the bonds. Without the enzyme, very few
reactions would have the energy to take place.
◉A scientist measured the rate of removal of amino acids from a
polypeptide with and without an enzyme present. With the enzyme
present, 578 amino acids were released per second. Without the enzyme,
3.0 × 10−9 amino acids were released per second.
Calculate by how many times the rate of reaction is greater with the
enzyme present. Give your answer in standard form.
2 marks . Answer: 578 = 5.78 x 10^.0 x 10^(-9) = 1.9266 x 10^11
---> 1.93 x 10^11
COMPLETE QUESTIONS AND CORRECT
VERIFIED ANSWERS ALREADY GRADED A+
100% GUARANTEED TO PASS CONCEPTS
◉The movement of Na⁺ out of the cell allows the absorption of glucose
into the cell lining the ileum.
Explain how. . Answer: The sodium ions are pumped into the blood from
epithelial cell, this means there is no NAT left in the epithelial cell.
Therefore, there is a diffusion gradient generated for the sodium ions
from the ileum into cell. The sodium ions that are moving in, by
facilitated diffusion, brings glucose with it.
◉Describe and explain two feature you would expect to find in a cell
specialised for absorption. . Answer: 1) Folded membrane so a large
surface area for absorption.
2) Large number of channel proteins so fast rate of absorption.
◉Figure shows the SGLT1 polypeptide so there is always NH₂ at one
end and COOH at the other end.
Describe how amino acids join to form a polypeptide so there is always
NH₂ at one end and COOH at the other end. . Answer: One amine group
, joins to a carboxyl group to form a peptide bond, so in the chain there is
a free amine group at one end and a free carboxyl group at the other.
Include a diagram ( drawn on paper test)
◉Formation of an enzyme-substrate complex increases the rate of
reaction.
Explain how.
2 marks . Answer: The formation of an enzyme-substrate complex
causes a reduction in the activation energy that is used for the reaction to
take place by bending the bonds. Without the enzyme, very few
reactions would have the energy to take place.
◉A scientist measured the rate of removal of amino acids from a
polypeptide with and without an enzyme present. With the enzyme
present, 578 amino acids were released per second. Without the enzyme,
3.0 × 10−9 amino acids were released per second.
Calculate by how many times the rate of reaction is greater with the
enzyme present. Give your answer in standard form.
2 marks . Answer: 578 = 5.78 x 10^.0 x 10^(-9) = 1.9266 x 10^11
---> 1.93 x 10^11
