C723 - Formulas and Samples Exam
Questions and Answers 100% Pass
test=A+(4*M)+P÷6
What does each letter stand for? - ANSWER-A is the optimistic time
MM is the most likely time
P is the pessimistic time
To determine the latest start, subtract the activity duration from the latest finish. -
ANSWER-LS = Duration - LF
To find the early finish, add the early start to the duration of each task. -
ANSWER-EF = ES + Duration of each task
Slack time (SL) is calculated using the following formula: - ANSWER-SL=LS−ES
How is the latest start time calculated? - ANSWER-Subtract the task duration from
the latest finish.
To determine the early finish, add the task duration to the early start. - ANSWER-
EF = Task duration + ES
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,________ = Cost of Items + Total Holding Cost + Total Ordering Cost -
ANSWER-Inventory Cost
___________ = (Crash Cost - Normal Cost) ÷ (Normal Duration - Crash
Duration) - ANSWER-Cost Slope
Based on Activity A as described below, what would be the cost to crash by 2 days
be?
Normal days = 12
Normal cost = $18,000
Crash days = 8
Crash cost = $22,000
Maximum time reduction = 4 - ANSWER-(22,000 - 18,000) ÷ (8 - 12)
4,000 ÷ 4 = 1,000
1,000 x 2 = 2,000
The answer is $2,000
Calculate duration estimates for the following situations:
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, A construction manager received an estimate from a sub-contracted plumber for
completion of the 2.5 bathrooms. The plumber thought it could be done in as few
as 20 labor hours, although this type of design usually takes 28 hours. The plumber
does remember that the last time, it took longer than usual and the labor hours
climbed to 36. Using the beta distribution method, how many hours should the
construction manager use as an estimate for the plumbing? - ANSWER-The
formula is:
Te = (o + 4m + p) / 6
28 hours
What would be the additional cost to crash Activity A by the maximum time
reduction period?
Normal days = 12
Normal cost = $18,000
Crash days = 8
Crash cost = $22,000
Maximum time reduction = 4 - ANSWER-(22,000 - 18,000) ÷ (12 - 8)
4,000 ÷ 4 = 1,000
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Questions and Answers 100% Pass
test=A+(4*M)+P÷6
What does each letter stand for? - ANSWER-A is the optimistic time
MM is the most likely time
P is the pessimistic time
To determine the latest start, subtract the activity duration from the latest finish. -
ANSWER-LS = Duration - LF
To find the early finish, add the early start to the duration of each task. -
ANSWER-EF = ES + Duration of each task
Slack time (SL) is calculated using the following formula: - ANSWER-SL=LS−ES
How is the latest start time calculated? - ANSWER-Subtract the task duration from
the latest finish.
To determine the early finish, add the task duration to the early start. - ANSWER-
EF = Task duration + ES
COPYRIGHT 2025 ALL RIGHTS RESERVED, TRUSTED AND VERIFIED 1
,________ = Cost of Items + Total Holding Cost + Total Ordering Cost -
ANSWER-Inventory Cost
___________ = (Crash Cost - Normal Cost) ÷ (Normal Duration - Crash
Duration) - ANSWER-Cost Slope
Based on Activity A as described below, what would be the cost to crash by 2 days
be?
Normal days = 12
Normal cost = $18,000
Crash days = 8
Crash cost = $22,000
Maximum time reduction = 4 - ANSWER-(22,000 - 18,000) ÷ (8 - 12)
4,000 ÷ 4 = 1,000
1,000 x 2 = 2,000
The answer is $2,000
Calculate duration estimates for the following situations:
COPYRIGHT 2025 ALL RIGHTS RESERVED, TRUSTED AND VERIFIED 2
, A construction manager received an estimate from a sub-contracted plumber for
completion of the 2.5 bathrooms. The plumber thought it could be done in as few
as 20 labor hours, although this type of design usually takes 28 hours. The plumber
does remember that the last time, it took longer than usual and the labor hours
climbed to 36. Using the beta distribution method, how many hours should the
construction manager use as an estimate for the plumbing? - ANSWER-The
formula is:
Te = (o + 4m + p) / 6
28 hours
What would be the additional cost to crash Activity A by the maximum time
reduction period?
Normal days = 12
Normal cost = $18,000
Crash days = 8
Crash cost = $22,000
Maximum time reduction = 4 - ANSWER-(22,000 - 18,000) ÷ (12 - 8)
4,000 ÷ 4 = 1,000
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