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BUAL 2650 Final Exam Review - Gupta questions and solutions
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BUAL 2650 Final Exam Review - Gupta questions and solutionsBUAL 2650 Final Exam Review - Gupta questions and solutionsBUAL 2650 Final Exam Review - Gupta questions and solutionsBUAL 2650 Final Exam Review - Gupta questions and solutions

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  • April 15, 2025
  • 11
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers

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  • bual 2650 final exam review gupta

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  • BUAL 2650
  • BUAL 2650

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BUAL2650FinalExamReview -Gupta e
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1. It is appropriate to use the uniform distribution to describe a continuous
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randomvariablex when:relativefrequenciesofall possiblevaluesofx areabout the
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same.
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2. Thenormalapproximationofthebinomialdistributionisappropriatewhen-
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:np e 5 and n(1
e
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3. Thefillweightofacertainbrandofadultcerealisnormallydistributedwith a
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mean of 910 grams and a standard deviation of 5 grams.We calculated
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the value of z for a specific box of this brand of cereal,and the z value was negative.
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This negative z value indicates that: the fill weight is less than 910 grams.
e
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4. Which of the following statements is not a property of the normal probability e
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distribution?:95.44percentofallpossibleobservedvaluesoftherandom variable x are
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within plus or minus three standard deviations of the population mean.
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5. If the random variable x is normally distributed,
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sible observed values of x will be within three standard deviations of the mean.:
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99.73
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6. The z value tells us the number of thatavalueofx is fromthe
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mean.: standard deviations
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7. A continuous probability distribution having a rectangular shape, where the
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probability is evenly distributed over an interval of numbers is a(n)
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distribution.: uniform
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8. The specific shape of each normal distribution is determined by its
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and .:mean, standard deviation. ne e
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9. Theareaunderthecurveofavalidcontinuousprobabilitydistributionmust
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.:equal 1 e
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10. values of the standard deviation result in a normal curve that is ne ne ne ne ne ne ne ne ne ne ne




wider and flatter.: Larger
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11. Themeanofastandardnormaldistributionisalwaysequalto e
n .:0 e
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12. Given that the length an athlete throws a hammer is a normal random variable ne ne ne ne ne ne ne ne ne ne ne ne ne




withmean50feetandstandarddeviation5feet,whatistheprobability he throws it
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no less than 55 feet?: .1587
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Z = (55 ne 50)/5 = 1
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P(X e 55) = 1 .8412 = .1587
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13. What is the probability that a standard normal random variable will be ne ne ne ne ne ne ne ne ne ne ne




between .3 and 3.2?: .3814
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14. For nonnormal populations, as the sample size (n) , the distri- bution of
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sample means approaches a(n)
ne distribution.: increases,
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normal
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1/11 ne ne

, BUAL2650FinalExamReview -Gupta e
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15. saysthatifthesamplesizeissufficientlylarge,thenthesample e
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means are approximately normally distributed.: The Central Limit Theorem
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16. Find P(x < 35) if ¼
= 40,x Ã= 16,n = 16.:.1056 ne ne ne ne ne ne e
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17. Packagesof sugarbagsforSweeterSugarInc.haveanaverageweight of 16 ne ne ne ne ne ne ne e
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ounces and a standard deviation of .2 ounces.The weights of the sugar packages
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are normally distributed.What is the probability that 16 randomly selected
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packages will have a weight in excess of 16.075 ounces?: .0668
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18. FindP(x > 172),if ¼ = 175 and 2 Ã(variance) = 9.:.8413 e
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z=(172
ne 175)/9- = 1P(x>172)=1.00 .1587
19. The exact spread of the t distribution depends on the ne.:numberof ne ne ne ne ne ne ne ne ne e
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degrees of freedom
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20. When the population is normally distributed, population standard devia- tion ne ne ne ne ne ne ne ne ne




Ãi s unknown,andthesamplesizeisn=15,theconfidenceintervalforthe
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population mean ¼
ne is based on: the t distribution. ne ne ne ne ne ne ne




21. Asthestandarddeviation( )Ãdecreases,thewidthoftheconfidenceinterval
e
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.:decreases e
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22. A confidence interval for the population mean is an interval constructed
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around the
ne .: sample mean ne ne ne ne




23. Inamanufacturingprocess,arandomsampleof9manufacturedboltshas a
e
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mean length of 3 inches with a variance of .09 and is normally distributed. What is
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the 90 percent confidence interval for the true mean length of the manufactured
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bolt?: 2.8140 to 3.1860
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[x ±/t2,n 1(s/n )]= [3±1.86(.3/3)]=[3±.186]=[2.814, 3.186] ne ne




24. In a manufacturing process, a random sample of 36 manufactured bolts hasa
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mean length of 3 inches with a standard deviation of .3 inches.What is the 99
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percent confidence interval for the true mean length of the manufac- tured bolt?:
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2.864 to 3.136
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[x±t±/2n, 1(s/n )]=[3±2.719(.3/6)]=[3±.136]=[2.864, 3.136] ne




25. In a manufacturing process, we are interested in measuring the average
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length of a certain type of bolt.Past data indicate that the standard deviation is .25
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inches. How many manufactured bolts should be sampled in order to make us 95
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percent confident that the sample mean bolt length is within .02 inches of the true
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mean bolt length?: 601
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n=[(z±/2×s)/E]2=[(1.96×.25)/.02]2=600.25=601
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26. Rejecting a true null hypothesis is called a error.:TypeI ne ne ne ne ne ne ne ne e
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27. A recent study conducted by the state government attempts to determine
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whether the voting public supports a further increase in cigarette taxes.The
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opinion poll recently sampled 1,500 voting age citizens.1,020 of the sampled
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citizens were in favor of an increase in cigarette taxes.The state government
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2/11 ne ne

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