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Solutions for Beginning Algebra 9th Edition by John Tobey, Jeffrey Slater, Jenny Crawford, Jamie Blair, All Chapters 1-10

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Solutions for Beginning Algebra 9th Edition by John Tobey, Jeffrey Slater, Jenny Crawford, Jamie Blair, All Chapters 1-10

Institution
Beginning Algebra 9th Edition
Course
Beginning Algebra 9th Edition











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Institution
Beginning Algebra 9th Edition
Course
Beginning Algebra 9th Edition

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Uploaded on
April 4, 2025
Number of pages
291
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

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solutions
M

Beginning
ED


Algebra, 9th
PA
PE

edition
RS

Authors:
_S

John Tobey Jr., Jeffrey Slater, Jamie Blair
TU

◊ All CHAPtERs

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, Chapter 0
0.1 Exercises 8
25 1
26. = 3 25 = 8
M
13 3 24 3
2. : 17 is the denominator
17 1

3 17 11
ED
4. 1: or 79 2
3 17 28. = 7 79 = 11
7 7 7
3 09
6. 3
4 7
2
PA
20 5 × 4 5 15
8. = = 124 4 1
24 6 × 4 6 30. = 8 124 = 15 = 15
8 8 8 2
8 1× 8 1
10. = = 44
PE
48 6 × 8 6 40
4
72 18 × 4
12. = =4
18 18 × 1
2 (4 × 5) + 2 20 + 2 22
32. 4 = = =
RS
32 32 × 1 1 5 5 5 5
14. = =
64 32 × 2 2
1 (5 × 12) + 1 60 + 1 61
34. 5 = = =
33 11 × 3 3 12 12 12 12
16. = =
_S
55 11 × 5 5 5 (1 × 6) + 5 6 + 5 11
36. 1 = = =
6 6 6 6
63 9 × 7 7
18. = =
81 9 × 9 9 2 (6 × 3) + 2 18 + 2 20
38. 6 = = =
TU
3 3 3 3 3
19 4
20. = 5 19 = 3
5 5 1 (10 × 9) + 1 90 + 1 91
15 40. 10 = = =
4 9 9 9 9
VI
78
54
7
5 42. = 78 ÷ 6
22. = 7 54 = 7 6
7 49 7 13
5 6 78
A?
6
6 18
41 5
24. = 6 41 = 6 18
6 36 6 0
5 78
?
= 13
6




Copyright © 2017 Pearson Education, Inc. 1

, Chapter 0: A Brief Review of Arithmetic Skills ISM: Beginning Algebra


5 ? 5 × 6 30 0.2 Exercises
44. = ⇒ =
9 54 9 × 6 54
2. You must change the fractions to equivalent
fractions with a common denominator.
5 ? 5 × 5 25
46. = ⇒ =
M
9 45 9 × 5 45 21 17
4. and
30 20
13 ? 13 × 3 39
48. = ⇒ = 30 = 2 ⋅ 3 ⋅ 5
17 51 17 × 3 51 20 = 2 ⋅ 2 ⋅ 5
ED
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
10 ? 10 × 4 40
50. = ⇒ =
15 60 15 × 4 60 5 1
6. and
18 24
7 ? 7 × 5 35 18 = 2 ⋅ 3 ⋅ 3
52. = ⇒ =
PA
8 40 8 × 5 40 24 = 2 ⋅ 2 ⋅ 2 ⋅ 3
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3 = 72
45 ? 45 × 2 90
54. = ⇒ =
50 100 50 × 2 100 5 7
8. and
16 48
PE
20 5× 4 5 16 = 2 ⋅ 2 ⋅ 2 ⋅ 2
56. = =
424 106 × 4 106 48 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3 = 48
1400 70 × 20 70
58. = =
2420 121× 20 121 11 7
RS
10. and
12 20
3 3 12 = 2 ⋅ 2 ⋅ 3
60. = is raisins
1+ 3 +1 5 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
1+ 3
_S
4
62. = does not contain nuts 7 8
1+ 3 +1 5 12. and
30 45
6 6 3× 2 3 30 = 2 ⋅ 3 ⋅ 5
64. = = =
6 + 8 14 7 × 2 7 45 = 3 ⋅ 3 ⋅ 5
TU
3 LCD = 2 ⋅ 3 ⋅ 3 ⋅ 5 = 90
of the students enrolled in 1994 were male.
7 1 3 9
14. , , and
Classroom Quiz 0.1 7 14 35
7=7
VI
56 7 × 8 7 14 = 2 ⋅ 7
1. = = 35 = 5 ⋅ 7
88 11× 8 11
LCD = 2 ⋅ 5 ⋅ 7 = 70
11 (5 × 14) + 11 70 + 11 81
A?
2. 5 ⇒ = = 3 5 11
14 14 14 14 16. , , and
8 12 42
109 1 8=2⋅2⋅2
3. =9 12 = 2 ⋅ 2 ⋅ 3
12 12
42 = 2 ⋅ 3 ⋅ 7
9
?
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 7 = 168
12 109
108
1


2 Copyright © 2017 Pearson Education, Inc.

, ISM: Beginning Algebra Chapter 0: A Brief Review of Arithmetic Skills


5 3 11 5 3 1 5 9 8 6 1
18. , and 44. + − = + − = =
8 14 16 24 8 3 24 24 24 24 4
8=2⋅2⋅2
14 = 2 ⋅ 7 1 1 25 13 75 52 127
46. 3 + 2 = + = + = =5
7
M
16 = 2 ⋅ 2 ⋅ 2 ⋅ 2 8 6 8 6 24 24 24 24
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 7 = 112
2 3 20 3 80 9 89 5
3 5 3+5 8 48. 6 + = + = + = =7
20. + = = 3 4 3 4 12 12 12 12
ED
11 11 11 11
2 3 37 15 148 75 73 13
11 2 11 − 2 9 3 50. 7 − 3 = − = − = =3
22. − = = = 5 4 5 4 20 20 20 20
15 15 15 15 5
8 3 113 13 113 39 74 14
3 13 3 × 3 13 × 4 9 52 61 52. 7 −2 = − = − = =4
PA
1
24. + = + = + = or 1 15 5 15 5 15 15 15 15
20 15 20 × 3 15 × 4 60 60 60 60
1 1 22 13 66 91 157 10
4 3 4 × 7 3 × 5 28 15 13 54. 3 + 4 = + = + = =7
26. − = − = − = 7 3 7 3 21 21 21 21
5 7 5 × 7 7 × 5 35 35 35
PE
1 2 37 17 20 2
3 1 3 × 3 1× 8 9 8 17 56. 12 − 5 = − = =6
28. + = + = + = 3 3 3 3 3 3
8 3 8 × 3 3 × 8 24 24 24
12 1 129 118 247
2 7 2× 2 7×3 4 21 25 5 58. 9 +9 = + = = 19
+ = + = + = = 13 13 13 13 13
RS
30.
15 10 15 × 2 10 × 3 30 30 30 6
19 3 19 9 28 14
21 23 21 × 2 23 42 23 19 60. + = + = =
32. − = − = − = 30 10 30 30 30 15
12 24 12 × 2 24 24 24 24
_S
2 2 17 37 85 111 196 1
13 1 13 1× 3 13 3 10 2 62. 5 + 7 = + = + = = 13
34. − = − = − = = 3 5 3 5 15 15 15 15
15 5 15 5 × 3 15 15 15 3
15 3 15 9 6 1
7 5 7 × 9 5 × 4 63 20 83 11 64. − = − = =
36. + = + = + = or 2 24 8 24 24 24 4
TU
4 9 4 × 9 9 × 4 36 36 36 36
1 1 19 17 76 51 25 1
4 7 1 36 49 21 106 43 66. 6 − 4 = − = − = =2
38. + + = + + = or 1 3 4 3 4 12 12 12 12
7 9 3 63 63 63 63 63
3 1 363 261
68. 45 − 26 = −
VI
1 3 4 1× 7 3× 6 4× 4
40. + + = + + 8 10 8 10
12 14 21 12 × 7 14 × 6 21 × 4 1815 1044
7 18 16 = −
= + + 40 40
84 84 84 771
A?
41 =
= 40
84 11
= 19
40
1 2 11 1 × 3 2 × 5 11
42. + − = + −
5 3 15 5 × 3 3 × 5 15 2 5 5 5 30 5 35 17
?
3 10 11 70. 1 + = + = + = =1
= + − 3 18 3 18 18 18 18 18
15 15 15
2
=
15

Copyright © 2017 Pearson Education, Inc. 3

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