C784 - Review Tests - 4,5,6,7
The accurate answer is c. This histogram reveals a distribution this is definitely skewed as the
lengthy tail of the graph is to the proper of the height.
A) Normal
b) Negatively Skewed
c) Positively Skewed
d) Cannot determine
The solution is c. Use the Empirical Rule to decide that 95p.Cninety five% of the diastolic blood
strain values might be inside two preferred deviations of the imply.
Therefore, the top restriction could be:
sixty five.Three+2(eleven.3)=sixty five.3+22.6=87.965.Three+2(eleven.3)=65.3+22.6=87.9
And the lower limit may be:
65.Three−2(11.3)=sixty five.Three−22.6=42.765.Three-2(eleven.Three)=sixty five.3-22.6=42.7
Therefore, 95percentninety five% of the diastolic blood pressures could be among forty
two.742.7 mm Hg and 87.987.9 mm Hg.
2)Adult diastolic blood pressures are commonly dispensed. The imply is sixty five.3 mm Hg and
the usual deviation is 11.Three mm Hg. What values might 95%ninety five% of the data fall
among?
A) forty seven.2 and 89.7
b) 42.2 and 86.Nine
c) 42.7 and 87.Nine
d) forty one.6 and 86.Eight
The answer is b. The Standard Deviation Rule says that 68% of the values will fall within eleven
general deviation of the mean.
,3) Assuming that adult diastolic blood pressures are generally disbursed, what is the
approximate percent of adults who have diastolic blood pressures inside eleven widespread
deviation of the suggest, or between fifty four.0mm Hg and 76.6 mm Hg?
A) 50%
b) sixty eight%
c) ninety five.Four%
d) ninety nine.7%
The solution is d. The variety is the difference among the smallest and best values (most and
minimum) of a facts set. The minimum cost is 48; the maximum is 84. 84 -forty eight = 36
4) What is the range of the subsequent statistics set?
A) 26
b) 28
c) 32
d) 36
The answer is a. To discover the suggest, step one is to feature all the values together. Then
divide that sum (784) via the number of values in the statistics set (12) . 78/412=65.3
5) What is the suggest of the subsequent statistics set?
A) 65.Three
b) sixty nine.2
c) 61.6
d) sixty four.Four
, The solution is c. As there are a fair quantity of data points in this data set, the median is
half-way between one hundred twenty five and one hundred twenty five. Therefore, the second
quartile (Q2), additionally referred to as the median, =one hundred twenty five.
6) What is 2nd quartile (Q2Q2) of this facts set?
A) 123
b) 124
c) 125
d) one hundred twenty five.5
The answer is d. Find the median, or mid-factor, of the data set:78 eighty five 87 ninety a
hundred a hundred and five 115 117 123 one hundred twenty five one hundred twenty five 128 a
hundred thirty five one hundred forty 152 159 160 165 169 17978 85 87 90 a hundred a
hundred and five one hundred fifteen 117 123 125 a hundred twenty five 128 one hundred thirty
five 140 152 159 a hundred and sixty one hundred sixty five 169 179To locate the primary
quartile (Q1Q1) become aware of the median of the lower 1/2 of the facts set:78 eighty five 87
ninety a hundred one zero five 115 117 123 a hundred twenty five 125 128 135 140 152 159 a
hundred and sixty 165 169 17978 85 87 90 one hundred a hundred and five one hundred fifteen
117 123 125 125 128 a hundred thirty five one hundred forty 152 159 one hundred sixty one
hundred sixty five 169 179The median of the decrease 1/2 of the statistics set falls between
100100 and 105105. Therefore the first quartile(Q1Q1) =(100+one hundred and five)2=102.5
7) What is the first quartile (Q1Q1) of this statistics set?
A) one hundred
b) 103.Five
c) one zero five
d) 102.Five
Correct. The solution is b. Find the median, or mid-point, of the data set:78 eighty five 87 ninety
one hundred a hundred and five one hundred fifteen 117 123 125 125 128 one hundred thirty
The accurate answer is c. This histogram reveals a distribution this is definitely skewed as the
lengthy tail of the graph is to the proper of the height.
A) Normal
b) Negatively Skewed
c) Positively Skewed
d) Cannot determine
The solution is c. Use the Empirical Rule to decide that 95p.Cninety five% of the diastolic blood
strain values might be inside two preferred deviations of the imply.
Therefore, the top restriction could be:
sixty five.Three+2(eleven.3)=sixty five.3+22.6=87.965.Three+2(eleven.3)=65.3+22.6=87.9
And the lower limit may be:
65.Three−2(11.3)=sixty five.Three−22.6=42.765.Three-2(eleven.Three)=sixty five.3-22.6=42.7
Therefore, 95percentninety five% of the diastolic blood pressures could be among forty
two.742.7 mm Hg and 87.987.9 mm Hg.
2)Adult diastolic blood pressures are commonly dispensed. The imply is sixty five.3 mm Hg and
the usual deviation is 11.Three mm Hg. What values might 95%ninety five% of the data fall
among?
A) forty seven.2 and 89.7
b) 42.2 and 86.Nine
c) 42.7 and 87.Nine
d) forty one.6 and 86.Eight
The answer is b. The Standard Deviation Rule says that 68% of the values will fall within eleven
general deviation of the mean.
,3) Assuming that adult diastolic blood pressures are generally disbursed, what is the
approximate percent of adults who have diastolic blood pressures inside eleven widespread
deviation of the suggest, or between fifty four.0mm Hg and 76.6 mm Hg?
A) 50%
b) sixty eight%
c) ninety five.Four%
d) ninety nine.7%
The solution is d. The variety is the difference among the smallest and best values (most and
minimum) of a facts set. The minimum cost is 48; the maximum is 84. 84 -forty eight = 36
4) What is the range of the subsequent statistics set?
A) 26
b) 28
c) 32
d) 36
The answer is a. To discover the suggest, step one is to feature all the values together. Then
divide that sum (784) via the number of values in the statistics set (12) . 78/412=65.3
5) What is the suggest of the subsequent statistics set?
A) 65.Three
b) sixty nine.2
c) 61.6
d) sixty four.Four
, The solution is c. As there are a fair quantity of data points in this data set, the median is
half-way between one hundred twenty five and one hundred twenty five. Therefore, the second
quartile (Q2), additionally referred to as the median, =one hundred twenty five.
6) What is 2nd quartile (Q2Q2) of this facts set?
A) 123
b) 124
c) 125
d) one hundred twenty five.5
The answer is d. Find the median, or mid-factor, of the data set:78 eighty five 87 ninety a
hundred a hundred and five 115 117 123 one hundred twenty five one hundred twenty five 128 a
hundred thirty five one hundred forty 152 159 160 165 169 17978 85 87 90 a hundred a
hundred and five one hundred fifteen 117 123 125 a hundred twenty five 128 one hundred thirty
five 140 152 159 a hundred and sixty one hundred sixty five 169 179To locate the primary
quartile (Q1Q1) become aware of the median of the lower 1/2 of the facts set:78 eighty five 87
ninety a hundred one zero five 115 117 123 a hundred twenty five 125 128 135 140 152 159 a
hundred and sixty 165 169 17978 85 87 90 one hundred a hundred and five one hundred fifteen
117 123 125 125 128 a hundred thirty five one hundred forty 152 159 one hundred sixty one
hundred sixty five 169 179The median of the decrease 1/2 of the statistics set falls between
100100 and 105105. Therefore the first quartile(Q1Q1) =(100+one hundred and five)2=102.5
7) What is the first quartile (Q1Q1) of this statistics set?
A) one hundred
b) 103.Five
c) one zero five
d) 102.Five
Correct. The solution is b. Find the median, or mid-point, of the data set:78 eighty five 87 ninety
one hundred a hundred and five one hundred fifteen 117 123 125 125 128 one hundred thirty
