2023 AQA GCSE BIOLOGY 8461/1F Paper 1 Foundation Tier Question Paper & F Mark scheme (Merged) June 2023 [VERIFIED]

2023 AQA GCSE BIOLOGY 8461/1F Paper 1 Foundation Tier Question Paper & F Mark scheme (Merged) June 2023 [VERIFIED] GCSE BIOLOGY Foundation Tier Paper 1F Tuesday 16 May 2023 Morning Time allowed: 1 hour 45 minutes Materials For this paper you must have: • a ruler • a scientific calculator. Instructions • Use black ink or black ball-point pen. • Pencil should only be used for drawing. • Fill in the boxes at the top of this page. • Answer all questions in the spaces provided. • If you need extra space for your answer(s), use the lined pages at the end of this book. Write the question number against your answer(s). • Do all rough work in this book. Cross through any work you do not want to be marked. • In all calculations, show clearly how you work out your answer. For Examiner’s Use Question Mark 1 2 3 4 5 6 7 TOTAL Information • The maximum mark for this paper is 100. • The marks for questions are shown in brackets. • You are expected to use a calculator where appropriate. • You are reminded of the need for good English and clear presentation in your answers. *JUN2384611F01* IB/M/Jun23/E19 8461/1F 2 Answer all questions in the spaces provided. 0 1Plants are made of cells, tissues and organs. 0 1 . 1 Which part of a plant is the largest? [1 mark] Tick ( ) one box. A guard cell A leaf A root hair Students investigated the effect of concentration of salt solution on the mass of pieces of potato. This is the method used. 1. Cut two pieces of potato to the same size. 2. Record the mass of each piece of potato. 3. Place one piece of potato into a beaker containing a dilute salt solution. 4. Place the other piece of potato into a beaker containing a concentrated salt solution. 5. After 20 minutes, remove each piece of potato from its solution. 6. Record the change in mass of each piece of potato. 7. Repeat steps 1 to 6 two more times. Table 1 shows the results. Table 1 Change in mass of piece of potato in grams Solution Test 1 Test 2 Test 3 Mean Dilute salt solution 1.1 1.1 1.4 X Concentrated salt solution −7.2 −6.8 −32.4 −7.0 Do not write outside the box *02* IB/M/Jun23/8461/1F 3 0 1 . 2Calculate mean value X in Table 1. [2 marks] X = grams There is an anomalous result for the concentrated salt solution in Table 1. 0 1 . 3Draw a ring around the anomalous result in Table 1. [1 mark] 0 1 . 4 What did the students do with the anomalous result when calculating the mean in Table 1? [1 mark] 0 1 . 5 What name is given to a variable that is kept the same during an investigation? [1 mark] Tick ( ) one box. Control variable Dependent variable Independent variable Question 1 continues on the next page Turn over ► *03* IB/M/Jun23/8461/1F Do not write outside the box 4 0 1 . 6 One variable the students kept the same during the investigation was the size of the pieces of potato. Which other variable did the students keep the same? [1 mark] Tick ( ) one box. Change in mass of pieces of potato Concentration of salt solution Time in the salt solution 0 1 . 7 The pieces of potato in the concentrated salt solution decreased in mass. Complete the sentence. Choose the answer from the box. [1 mark] excretion osmosis respiration Water moved out of the potato by the process of . Do not write outside the box *04* IB/M/Jun23/8461/1F 5 0 1 . 8 The potato cells have a partially permeable membrane. Which particles can pass through a partially permeable membrane? [1 mark] Tick ( ) one box. No particles Some particles All particles 0 1 . 9How could the students improve their inv