MAT 136 EXAM UPDATED QUESTIONS AND ANSWERS SOUTHERN NEW HAMPSHIRE

MAT 136 EXAM UPDATED QUESTIONS AND ANSWERS SOUTHERN NEW HAMPSHIRE √ 2⋅9 - Cancel the common factors of 18 and 16 which would be 2 2⋅8 √9 - Rewrite 8 √9 - as √8 3 - The squareroot of 9 = 3, factor 4 out of 8 √4(2) 3 - The squareroot of 4 = 2, remove 2 from radical 2√2 ( 3 ) ⋅ ( √2 ) - Multiply togther and simplify 2√2 √2 (3⋅√2) 2(√2) 2 (3⋅√2) 2 n x x 1 1 - use √a = a n to rewrite √2 as 2 2 and simplify 2(2 2 ) (3√2) 2⋅2 (3√2) 4 Ungraded Grade: 0/1.0 lOMoAR cPSD| 4/19/2021 Southern New Hampshire University - Gradebook Question Total grade: 1.0×1/2 + 0.0×1/2 = 50%√+ 0%18 = √ 2⋅9 Factor perfect squares from the radicand. Feedback: 16 16 = 3 √2 Simplify. 4 Q2 0/0.0 Auto graded Grade: 1/1.0 Show your work and explain, in your own words, how you arrived at your answer. Answers with no relevant explanations may receive reduced or no credit. 2/22 Solve for x. Enter the exact answer. x = 6 (x + 3) − 37 = x + 6 Your response Correct response 5 5 lOMoAR cPSD| 4/19/2021 Southern New Hampshire University - Gradebook Question 6 (x + 3) − 37 - Simplify the left side of the equaiton 6 x + 18 − 37 - 6*x and 6*3 6 x − 19 = x + 6 6 x − 19 − x = 6 - move x to the left side of the equation by subtracting from both sides 5 x − 19 = 6 - subtract x from 6x 5 x = 6 + 19 - Move 19 to the right side of the equation by adding 19 to both sides 5 x = 25 - Add 6+19 x = 25 - Move 5 to the right side by dividing by 5 5 x = 5 Ungraded Grade: 0/1.0 Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0% Feedback: Apply standard algebraic properties. 6 (x + 3) − 37 = x + 6 6x + 18 − 37 = x + 6 6x − 19 = x + 6 5x = 25 x = 25 5 x = 5 Apply the distributive property. Combine like terms. Place x- terms on one side and simplify. Multiply both sides by 1 , the reciprocal of 5. 5 Q3 0/0.0 View Original Response Unfiltered Response