May 2020 & Oct 2019 Exam suggested solutions
BNU1501
FACILITATOR:
PATRICIA HERSELMAN
BNU1501
© Patricia Herselman
, 1
May/Jun 2020
May/June 2020
1. 2 35 ÷ 5 + 2 – ((3 x 4 – 2) – (18 – 3 x 4))
= 7 + 2 – ((12 – 2) – (18 – 12))
= 9 – (10 – 6)
= 9 – 10 + 6
2. 1 (−8 – 5𝑥 3 + 4𝑥) − [(2𝑥 + 𝑥 3 ) + (𝑥 + 7)]
= −8 – 5𝑥 3 + 4𝑥 − 3𝑥 + 𝑥 3 + 7
= -15 – 6𝑥 3 + 𝑥
3
3. 1 2√25 − √54 + √9 + 42 = 12.5339
23 √2 − 3√2+5 = 12.5339
3
𝑎3 𝑥 𝑏5 1
4. 3 √
𝑏9 𝑥 𝑎5
= 𝑎 𝑥 𝑏2 = 𝑎−1 𝑏−2 = (𝑎𝑏 2 )−1
1
5. 4 (𝑥 + 3)/2 = (𝑥 + 3)
2
5
6. 2 −1(𝑥 − 3) + 2𝑥 = −3𝑥 + 2
5
−𝑥 + 3 + 2𝑥 = −3𝑥 +
2
5
−𝑥 + 2𝑥 + 3𝑥 = −3
2
1 1
4𝑥 = 2 − 3 =
2 2
1 1
𝑥 = −2 x 4
1
=−
8
1 1
7. 1 1 = 5 𝑥 + 70 𝑚𝑖𝑛 + 3 𝑥
1 1
70 min = 1 − −
5 3
7
70 min =
15
15
70 min 𝑥 = 150 𝑚𝑖𝑛
7
1 1
8. 4 𝑎 (𝑏 + 𝑐 ) = 1
𝑎 = 1(𝑏 + 𝑐)
𝑎 = 𝑏+𝑐
BNU1501
© Patricia Herselman
BNU1501
FACILITATOR:
PATRICIA HERSELMAN
BNU1501
© Patricia Herselman
, 1
May/Jun 2020
May/June 2020
1. 2 35 ÷ 5 + 2 – ((3 x 4 – 2) – (18 – 3 x 4))
= 7 + 2 – ((12 – 2) – (18 – 12))
= 9 – (10 – 6)
= 9 – 10 + 6
2. 1 (−8 – 5𝑥 3 + 4𝑥) − [(2𝑥 + 𝑥 3 ) + (𝑥 + 7)]
= −8 – 5𝑥 3 + 4𝑥 − 3𝑥 + 𝑥 3 + 7
= -15 – 6𝑥 3 + 𝑥
3
3. 1 2√25 − √54 + √9 + 42 = 12.5339
23 √2 − 3√2+5 = 12.5339
3
𝑎3 𝑥 𝑏5 1
4. 3 √
𝑏9 𝑥 𝑎5
= 𝑎 𝑥 𝑏2 = 𝑎−1 𝑏−2 = (𝑎𝑏 2 )−1
1
5. 4 (𝑥 + 3)/2 = (𝑥 + 3)
2
5
6. 2 −1(𝑥 − 3) + 2𝑥 = −3𝑥 + 2
5
−𝑥 + 3 + 2𝑥 = −3𝑥 +
2
5
−𝑥 + 2𝑥 + 3𝑥 = −3
2
1 1
4𝑥 = 2 − 3 =
2 2
1 1
𝑥 = −2 x 4
1
=−
8
1 1
7. 1 1 = 5 𝑥 + 70 𝑚𝑖𝑛 + 3 𝑥
1 1
70 min = 1 − −
5 3
7
70 min =
15
15
70 min 𝑥 = 150 𝑚𝑖𝑛
7
1 1
8. 4 𝑎 (𝑏 + 𝑐 ) = 1
𝑎 = 1(𝑏 + 𝑐)
𝑎 = 𝑏+𝑐
BNU1501
© Patricia Herselman