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, a
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, a
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, 3. A patient/client consumed oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. What is
the total number of ounces consumed that should be documented for the patient/client?
a. 3 3/4
b. 4 5/12
c. 4 2/3
d. 4 4/9
@
ANS: B
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
multiplying the whole number by the denominator and then adding that total to the numerator. For the
coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
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= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find
the least common denominator (LCD). For 2, 3, and 4, the LCD =
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then
multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee),
8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added
together and the fraction is reduced to the lowest terms.
lu
Format: Multiple Choice
Chapter: 1
ss
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Analyze
Difficulty: Difficult
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
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Integrated Process: Communication and Documentation
Objective: 1, 2
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
vi
the nurse document as consumed? WWW.TBSM.WS
a. 360
b. 420
a
c. 510
d. 600
ANS: B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
milliliters consumed, multiply 180 7/3 ( ). When a mixed number is present, change it to an
improper fraction by multiplying the whole number by the denominator and then adding that total to
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Analyze
Difficulty: Difficult
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
Integrated Process: Communication and Documentation
Objective: 1, 2
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were
gained since admission?
a. 0.78
b. 0.88
______________________________________________________________________________________________
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vi
tu
ss
lu
Ap
@
, a
vi
tu
ss
lu
Ap
@
, a
vi
tu
ss
lu
Ap
@
, 3. A patient/client consumed oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. What is
the total number of ounces consumed that should be documented for the patient/client?
a. 3 3/4
b. 4 5/12
c. 4 2/3
d. 4 4/9
@
ANS: B
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
multiplying the whole number by the denominator and then adding that total to the numerator. For the
coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
Ap
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find
the least common denominator (LCD). For 2, 3, and 4, the LCD =
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and then
multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee),
8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators are added
together and the fraction is reduced to the lowest terms.
lu
Format: Multiple Choice
Chapter: 1
ss
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Analyze
Difficulty: Difficult
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
tu
Integrated Process: Communication and Documentation
Objective: 1, 2
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
vi
the nurse document as consumed? WWW.TBSM.WS
a. 360
b. 420
a
c. 510
d. 600
ANS: B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
milliliters consumed, multiply 180 7/3 ( ). When a mixed number is present, change it to an
improper fraction by multiplying the whole number by the denominator and then adding that total to
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Analyze
Difficulty: Difficult
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
Integrated Process: Communication and Documentation
Objective: 1, 2
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms were
gained since admission?
a. 0.78
b. 0.88
______________________________________________________________________________________________
2|Page
www.PlusBay.Plus
Downloaded
Downloaded by:
by: Examsstudy
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earn £756
$1.236
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