MEO
Physicstestbank
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For mid- t
term Grade 10
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Secondsemester
t
,1) At sea level, the average atmospheric pressure is 760 mmHg. Howm
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any
kilopascals is this? t t
a) 1.013 kPa t
b) 10.13 kPa t
c) 101.3 kPa t
d) 1013 kPa t t
Answer: C t
2) Which would be the least likely to sink into soft ground?
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a) a loaded lorry with six wheels
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b) a loaded lorry with four wheels
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c) an empty lorry with four wheels
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d) an empty lorry with six wheelsA
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nswer: D t
3) Water boils on Mount Everest at a temperature...
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a) less than 100 degrees Celsius because Mount Everest is always cold
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b) less than 100 degrees Celsius because there is less atmosphericpr
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essure
c) higher than 100 degrees Celsius because of the high altitude.
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d) water always boils at the same temperature no matter where it is onear
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th
,Answer: B t
4)When the atmospheric pressure at the surface of a lake is 1 Atm,fin
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d the lake depth when the pressure at its base is 3Atm? Knowingthat : (
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P water =1000 kg/m3 , Pa=1,013 x10* N/m^2, g=10m/s^2)?
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a) 30.39 m
t t
b) 20.673 m
t t
c) 9.717 m
t t
d) 10.13
t
Answer: A t
Explanation : pressure at base = 3* 1.013* 10^5 = 303900
t t t t t t t t t t ,
𝜌𝑔ℎ=30 t
3900
1000*10* h= 303900 t t
H= 30.39 m.
t t
5)When a barometer is put at a top of a mountain, the height ofme
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rcury column in its tube
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a) 76 cmt
b) 78 cm t
c) 74 cmt
d) 80 cm A
t t
nswer : C t t
, 6)If a uniform body weighs 50N in air and 30 N in water, its specificgra
t t t t t t t t t t t t t t t
vity equals ... t t
a) 1.5 t
b) 1.67 t
c) 2.5 t
d) 3 t
Answer: B t
Explanation : 50 N = m x 9.81 m/s^2m t t t t t t t t t t
= 5.1 kg
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Next, we can use the weight of the object in water to determine thebuoy
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ant force acting on the object:
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weight in water = force due to gravity on the displaced water =buoya
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nt force t
30 N = (volume of object submerged in water) x (density of water) x g
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volume of object submerged in water = 30 N / (1000 kg/m^3 x 9.81m/s^2
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) = 0.00305 m^3
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Since the object is uniform, the volume of the submerged part isequ
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al to its total volume, so the density of the object can be calculated a
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s:
Physicstestbank
t t t
For mid- t
term Grade 10
t t
Secondsemester
t
,1) At sea level, the average atmospheric pressure is 760 mmHg. Howm
t t t t t t t t t t t
any
kilopascals is this? t t
a) 1.013 kPa t
b) 10.13 kPa t
c) 101.3 kPa t
d) 1013 kPa t t
Answer: C t
2) Which would be the least likely to sink into soft ground?
t t t t t t t t t t
a) a loaded lorry with six wheels
t t t t t
b) a loaded lorry with four wheels
t t t t t
c) an empty lorry with four wheels
t t t t t
d) an empty lorry with six wheelsA
t t t t t t
nswer: D t
3) Water boils on Mount Everest at a temperature...
t t t t t t t
a) less than 100 degrees Celsius because Mount Everest is always cold
t t t t t t t t t t
b) less than 100 degrees Celsius because there is less atmosphericpr
t t t t t t t t t t
essure
c) higher than 100 degrees Celsius because of the high altitude.
t t t t t t t t t
d) water always boils at the same temperature no matter where it is onear
t t t t t t t t t t t t t
th
,Answer: B t
4)When the atmospheric pressure at the surface of a lake is 1 Atm,fin
t t t t t t t t t t t t t
d the lake depth when the pressure at its base is 3Atm? Knowingthat : (
t t t t t t t t t t t t t t t
P water =1000 kg/m3 , Pa=1,013 x10* N/m^2, g=10m/s^2)?
t t t t t t t t
a) 30.39 m
t t
b) 20.673 m
t t
c) 9.717 m
t t
d) 10.13
t
Answer: A t
Explanation : pressure at base = 3* 1.013* 10^5 = 303900
t t t t t t t t t t ,
𝜌𝑔ℎ=30 t
3900
1000*10* h= 303900 t t
H= 30.39 m.
t t
5)When a barometer is put at a top of a mountain, the height ofme
t t t t t t t t t t t t t t
rcury column in its tube
t t t t
a) 76 cmt
b) 78 cm t
c) 74 cmt
d) 80 cm A
t t
nswer : C t t
, 6)If a uniform body weighs 50N in air and 30 N in water, its specificgra
t t t t t t t t t t t t t t t
vity equals ... t t
a) 1.5 t
b) 1.67 t
c) 2.5 t
d) 3 t
Answer: B t
Explanation : 50 N = m x 9.81 m/s^2m t t t t t t t t t t
= 5.1 kg
t t
Next, we can use the weight of the object in water to determine thebuoy
t t t t t t t t t t t t t t
ant force acting on the object:
t t t t t
weight in water = force due to gravity on the displaced water =buoya
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nt force t
30 N = (volume of object submerged in water) x (density of water) x g
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volume of object submerged in water = 30 N / (1000 kg/m^3 x 9.81m/s^2
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) = 0.00305 m^3
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Since the object is uniform, the volume of the submerged part isequ
t t t t t t t t t t t t
al to its total volume, so the density of the object can be calculated a
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s:
