Atom consists nucleus around electron cloud
of
·
a
Nucleus has
small and
protons and neutrons
·
mainly
is
·
Electric Charge Unit : C
↳ electron = 1 .
602x10" C
COULOMB'S LAW
q .
&Q2 exert an electric force
m
F = (k)
(g)
:
(q) K = constant
given = P 0 X10
.
distance between
r =
charges
2
+
-
*
Charges change direction
like attract
charges repel , opposite charges
his law that than the
states that for charged objects are much smaller
distance between them , the to the
overall
force is similar
Armof
the distance
-
two
charges and
inversely proportional to
- squared
Q #
balls table I ball # has
ping pong
on a
,
cm away
. charge of
ball #C
O
0X10" has 0x10"
charge of
H . -3 .
,
What
(e)
is
magnitude
/+ 2
?
>
-
IF1 =
/g /1qz)
.
convert to m = 0 01m
.
= /4 . 0 x 10") (1 .
0 x10 -")(-3 .
0 x10 -")/(1)
= 2 7 . X/0-5
has is the
if each ball a
magnitude have a mass
of 0 . 010
leg ,
what
the initial acceleration ?
magnitude of
F = ma
a = F/M
a = 2 7 X10 . -"/0 . 010
= 2 S . X 10' m/s
, Q #2
have X10-15
protons 3 00
. m
x10-2
mass : 1 . 673
Reg
2 = 1 . 6 x 10. C
F =
(4 . 0 X 10") /1 6x . 10
-
") (1 .
6 X10
-
"(
= 25 6 N
10 5)
:
13
.
.
00 X
if no
forces acting upon it, what is acceleration ?
F = ma
a = F/m
:
a = 25 6 . 1 . 673 X 10
a = 1 .
53 X1028
Q #3
3
charged particles ,
electron , proton and alpha particle (Het)
what is the
are
arranged ,
resultant
force on the
proton due to
electron (e) and
alpha (a) ?
(k)(q )(q2) / r2
e-
at T Fa =
,
-10 !
sX
1
2
x
= (4 0 x 10") (2) (1 . 6 X 10" "( (1 6 x10 "
.
-
?55!
.
.
[ 32 _
11 .
4 x 10
-
10)
1 4 x
.
10-10
8
N
-
= 2 35 x 10
.
& Ex = Fax + Fe-x Fe + =
(1)(q ) (q2)/r2 .
X 10-0) cos65
:
= 12 35 . x 10
-
8) + (1 6 .
= 3 26. X0-8 = <P .
0 x 10") /- 1 .
6 X 10" )(1 . 6 X10 -1")
(1 2 10) 2
-
X (0
&
.
Fy Fay Fey = +
= 1 6 X 10-8 N
.
= (0) + 11 6 X10
.
-
8) sin55
= 1 31
. x 10-8 N
-x
(3Fy)2 +
O-tan" (1.31 x100 o =
(3 26 x 100)
.
+ (1 . 31 x 10
:
)2
=
22
:
=
3 S1 X10 -8
.
of
·
a
Nucleus has
small and
protons and neutrons
·
mainly
is
·
Electric Charge Unit : C
↳ electron = 1 .
602x10" C
COULOMB'S LAW
q .
&Q2 exert an electric force
m
F = (k)
(g)
:
(q) K = constant
given = P 0 X10
.
distance between
r =
charges
2
+
-
*
Charges change direction
like attract
charges repel , opposite charges
his law that than the
states that for charged objects are much smaller
distance between them , the to the
overall
force is similar
Armof
the distance
-
two
charges and
inversely proportional to
- squared
Q #
balls table I ball # has
ping pong
on a
,
cm away
. charge of
ball #C
O
0X10" has 0x10"
charge of
H . -3 .
,
What
(e)
is
magnitude
/+ 2
?
>
-
IF1 =
/g /1qz)
.
convert to m = 0 01m
.
= /4 . 0 x 10") (1 .
0 x10 -")(-3 .
0 x10 -")/(1)
= 2 7 . X/0-5
has is the
if each ball a
magnitude have a mass
of 0 . 010
leg ,
what
the initial acceleration ?
magnitude of
F = ma
a = F/M
a = 2 7 X10 . -"/0 . 010
= 2 S . X 10' m/s
, Q #2
have X10-15
protons 3 00
. m
x10-2
mass : 1 . 673
Reg
2 = 1 . 6 x 10. C
F =
(4 . 0 X 10") /1 6x . 10
-
") (1 .
6 X10
-
"(
= 25 6 N
10 5)
:
13
.
.
00 X
if no
forces acting upon it, what is acceleration ?
F = ma
a = F/m
:
a = 25 6 . 1 . 673 X 10
a = 1 .
53 X1028
Q #3
3
charged particles ,
electron , proton and alpha particle (Het)
what is the
are
arranged ,
resultant
force on the
proton due to
electron (e) and
alpha (a) ?
(k)(q )(q2) / r2
e-
at T Fa =
,
-10 !
sX
1
2
x
= (4 0 x 10") (2) (1 . 6 X 10" "( (1 6 x10 "
.
-
?55!
.
.
[ 32 _
11 .
4 x 10
-
10)
1 4 x
.
10-10
8
N
-
= 2 35 x 10
.
& Ex = Fax + Fe-x Fe + =
(1)(q ) (q2)/r2 .
X 10-0) cos65
:
= 12 35 . x 10
-
8) + (1 6 .
= 3 26. X0-8 = <P .
0 x 10") /- 1 .
6 X 10" )(1 . 6 X10 -1")
(1 2 10) 2
-
X (0
&
.
Fy Fay Fey = +
= 1 6 X 10-8 N
.
= (0) + 11 6 X10
.
-
8) sin55
= 1 31
. x 10-8 N
-x
(3Fy)2 +
O-tan" (1.31 x100 o =
(3 26 x 100)
.
+ (1 . 31 x 10
:
)2
=
22
:
=
3 S1 X10 -8
.
