ISYE 6644 - final prep2 exam with correct answers

ISYE 6644 - final prep2 exam with correct ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




answers


If f(x, y) = cxy for all 0 < x < 1 and 1 < y < 2, where c is whatever
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




value makes this thing integrate to 1, then X and Y are ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




independent random variables - correct answer✔✔TRUE. ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




(Because f(x, y) = a(x)b(y) factors nicely, and there are no funny ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




limits.)


In our Arena Call Center example, it was possible for entities to
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




be left in the system when it shut down at 7:00 p.m. (even
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




though we stopped allowing customers to enter the system at ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




6:00 p.m.). - correct answer✔✔TRUE — because of the small
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




chance that a callback will occur. ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




An entity can be scheduled to visit the same resource twice,
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




with different service time distributions on the two visits! -
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




correct answer✔✔TRUE ||\\||\\ ||\\||\\




Arena has a built-in Input Analyzer tool that allows for the fitting ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




of certain distributions to data. - correct answer✔✔TRUE
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\

, The Kolmogorov-Smirnov test can be used both to see (i) if data
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




seem to fit to a particular hypothesized distribution and (ii) if
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




the data are independent. - correct answer✔✔FALSE. (It's just a
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




goodness-of-fit test.)
||\\||\\ ||\\||\\




Welch's method is a graphical technique to estimate truncation ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




(initialization bias) points for steady-state simulation. - correct ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




answer✔✔TRUE


If you are using a ranking-and-selection procedure and two
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




competitors happen to fall within the indifference-zone, then ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




you don't really care too much which one you end up selecting. -
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




correct answer✔✔TRUE. That's why it's called the IZ!
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




TRUE or FALSE? Sequential ranking-and-selection procedures
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




are designed to stop early if one alternative seems to be way
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




out in front of the others. - correct answer✔✔TRUE
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




Suppose, when designing a ranking-and-selection procedure, ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\




you have decided to increase the desired probability of correct
||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\ ||\\||\\