Pearson Edexcel A Level GCE In Biology A Salters - Nuffield (9BN0) Paper 2: Energy, Exercise and Co-ordination Mark Scheme (Results) Summer 2025

Pearson Edexcel A Level GCE In Biology A Salters - Nuffield (9BN0) Paper 2:
Energy, Exercise and Co-ordination Mark Scheme (Results) Summer 2025




Mark Scheme (Results)




Summer 2025




Pearson Edexcel A Level GCE
In Biology A Salters - Nuffield (9BN0)
Paper 2: Energy, Exercise and Co-ordination

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Summer 2025
Question Paper Log Number 78658A
Publications Code 9BN0_02_2506_MS
All the material in this publication is copyright
© Pearson Education Ltd 2025

,General Marking Guidance


 All candidates must receive the same
treatment. Examiners must mark the first
candidate in exactly the same way as they mark
the last.
 Mark schemes should be applied positively.
Candidates must be rewarded for what they have
shown they can do rather than penalised for
omissions.
 Examiners should mark according to the mark
scheme not according to their perception of
where the grade boundaries may lie.
 There is no ceiling on achievement. All marks on the mark
scheme should be used appropriately.
 All the marks on the mark scheme are
designed to be awarded. Examiners should
always award full marks if deserved, i.e. if the
answer matches the mark scheme. Examiners
should also be prepared to award zero marks if
the candidate’s response is not worthy of credit
according to the mark scheme.
 Where some judgement is required, mark schemes will
provide the principles by which marks will be
awarded and exemplification may be limited.
 When examiners are in doubt regarding the application
of the mark scheme to a candidate’s response, the
team leader must be consulted.
 Crossed out work should be marked UNLESS the
candidate has replaced it with an alternative response.

, Question Answer Additional Guidance Mark
Number
1 (a)(i) Example of calculation

 unit conversion correct (1) width on image is 5mm =
is 5 x 106 nm / 5 000 000 nm
or width of cisterna as 20 x10-6 mm
 correct answer derived by dividing by actual
size (1) 5 000 000 ÷ 20 =
(x) 250 000

ECF – 1 mark for x 25 000 (2)
Correct answer with no working gains full
marks

Question Answer Additional Guidance Mark
Number
1 (a)(ii) An answer that makes reference to two of the IGNORE reference to other organelles
following:
ALLOW a pair of centrioles on each side
 two pairs of centrioles (1) of the cell gains the first two marking
points
 centrioles at the poles of the cell (1)
(2)
 no {nucleus / nuclear envelope} is present (1) ALLOW nuclear membrane has broken
down