3rd TSSA Part A1 - Unit 1 2025/2026
Exam Questions and Corresponding
Answers with Surety of 100% Pass Mark
Solve the following equation for r2: Q = 2sL(T2-T1)/ln(r2/r1) when:
Q=1,500,000, s=30, T2=275, T1=22, L=10, r1=6. - 🧠ANSWER ✔✔6.639
Find 'u' if v² = u² + 2as, given that v = 34 m/s, a = 9.81 m/s², and s = 8 m. -
🧠ANSWER ✔✔31.6 m/s
An equation is a statement of: - 🧠ANSWER ✔✔Equality.
What is 'ln N' if log N = 3.825 - 🧠ANSWER ✔✔8.807
Solve (a + 5b) - 2(a - 4) = 3(2a + b) - 7(a - 3) for b: - 🧠ANSWER ✔✔6.5
The natural or Naperian logarithm of 0.00478 is: - 🧠ANSWER ✔✔-5.3433
Find the antilogarithm of 3.7996. - 🧠ANSWER ✔✔6303.76
COPYRIGHT©JOSHCLAY 2025/2026. YEAR PUBLISHED 2025. COMPANY REGISTRATION NUMBER: 619652435. TERMS OF USE. PRIVACY
STATEMENT. ALL RIGHTS RESERVED
1
Exam Questions and Corresponding
Answers with Surety of 100% Pass Mark
Solve the following equation for r2: Q = 2sL(T2-T1)/ln(r2/r1) when:
Q=1,500,000, s=30, T2=275, T1=22, L=10, r1=6. - 🧠ANSWER ✔✔6.639
Find 'u' if v² = u² + 2as, given that v = 34 m/s, a = 9.81 m/s², and s = 8 m. -
🧠ANSWER ✔✔31.6 m/s
An equation is a statement of: - 🧠ANSWER ✔✔Equality.
What is 'ln N' if log N = 3.825 - 🧠ANSWER ✔✔8.807
Solve (a + 5b) - 2(a - 4) = 3(2a + b) - 7(a - 3) for b: - 🧠ANSWER ✔✔6.5
The natural or Naperian logarithm of 0.00478 is: - 🧠ANSWER ✔✔-5.3433
Find the antilogarithm of 3.7996. - 🧠ANSWER ✔✔6303.76
COPYRIGHT©JOSHCLAY 2025/2026. YEAR PUBLISHED 2025. COMPANY REGISTRATION NUMBER: 619652435. TERMS OF USE. PRIVACY
STATEMENT. ALL RIGHTS RESERVED
1
