Exam (elaborations)
MATH 225 Midterm Exam 1 Complete with solutions.
- Course
- MATH 225
- Institution
- University
Solutions of First Midterm Exam 1.a) Show that the function y(x) = A Bex Ce2x satisfies the differential equation yJJJ − 3yJJ 2yJ = 0, where A, B, and C are arbitrary constants. Solution: y(x) = A Bex Ce2x, yJ(x) = Bex 2Ce2x, yJJ(x) = Bex 4Ce2x yJJJ(x) = Bex 8Ce2x Hence yJJJ −...
[Show more]