WGU C784 Objective Assessment (New 2024/ 2025 Update) Applied Healthcare Statistics | Qs & As| Grade A| 100% Correct (Verified Answers)

WGU C784 Objective Assessment (New 2024/
lOMo




2025 Update) Applied Healthcare Statistics | Qs
and As| 100% Correct| Grade A (Verified
Answers) ARcPSD| 9970737




Question
Alspecialistlsawl27lpatientslandlmadelthelfollowingldiagnoses:l
Sevenlhadltypel2ldiabetes.
Ninelhadlcoronarylheartldisease.
Threelhadlbothltypel2ldiabeteslandlcoronarylheartldisease.lWh
atlislthelprobabilityloflalpatientlbeingldiagnosedlwithltypel2ldiabeteslorlcoro
narylheartldisease?
a.lll7ll −llll9ll −lll3ll
27 27 27
l7ll ll9ll l3ll
b.ll1ll−ll( −ll −ll
27 27
)
27
l7lll ll9 l3ll
c.ll1ll−ll( +ll −ll )
ll
27 27llllllllll 27
l7ll ll9ll l3ll
d.ll +ll −ll
27 27 27

,Answerll
7/27l+l9/27l−l3/27

Brieflexplanation
P(typel2lORlheartldisease)l=lP(typel2)l+lP(heartldisease)l−lP(both)
lllllllllllllllllllllllllllllllllllllllllllllllllllllll=llllll7/27llllll+lllllllll9/27llllllllllll −lll3/27

Videos
ORlRulelvideol[10:30],llORlmeansl“Addlthenlsubtractlthelboth”l[7:36],land
AND,lOR,l&lIFlProbabilities:lKeywordlApproachl[23:48]
Pageslforladditionallpractice
Modulel7:l7.11.1-ProbabilityloflDependentlEvents


Question
Alrurallcommunitylcliniclseesleightlpatientslperlhour.lThelprobabilitylthatlalp
atientlisldiagnosedlwithlhighlbloodlpressurelisl0.63.lThelpatientslare
assumedltolbeldiagnosedlindependentlyloflotherlpatients.lWhatlislthe
probabilitylthatlnoneloflthelpatientslwilllbeldiagnosedlwithlhighlbloodlp
ressure?


a.l 0.378
b.l 0.638
c.l 1 l−l(0.63)8
d.l 1 l−l(0.37)8

Answer
0.378
Brieflexplanation
Usinglthelcomplementlrule,lwelfindlthatl1l−l0.63l=l0.37lislthelprobabilitylth
atlonelpatientldoeslnotlhavelhighlbloodlpressure.ll“Noneloflthelpatientslwill
lbeldiagnosedlwithlhighlbloodlpressure”lmeanslgettingl8lpatientslinlalrowl
wholdolnotlhavelhighlbloodlpressure.llSolthelanswerlisl(0.37)^8,las
thelpatients’lbloodlpressurelstatuseslarelindependentloflonelanother.
Video
ComplementlRulel[6:58]

, Pageslforladditionallpractice
Modulel7:l7.07-lComplementarylEventslandl7.09-
lIndependentlEventslandlthelMultiplicationlPrinciple

llQuestion
Alcountylhasl625lgrouplphysicianslpracticeslthatlprovidelthelfollowingl
services:
300lprovidelprimarylcarelservices
225lprovidelspecialtylcarelservices
100lprovidelbothlprimarylcarelandlspecialtylcarelservices
Whatlislthelprobabilityloflalphysicianlgrouplpracticelprovidinglprimarylcarels
erviceslorlspecialtylcarelservices?
a.l 1ll− (300 +ll225 +ll100)
625 625 625
300 225 100
b.ll +ll −l
625 625 625
225 100
c.ll300 +ll +l
625 625 625

625 625 625


Answerlll
300/625l+l225/625l−l100/625

Brieflexplanation
P(primarylcarelORlspecialtylcare)l=lP(primary)l+lP(specialty)l−lP(both)

, llllllllllll=ll300/625lll +lll 225/625lll −ll100/625

Videos
ORlRulelvideol[10:30],llORlmeansl“Addlthenlsubtractlthelboth”l[7:36],land
AND,lOR,l&lIFlProbabilities:lKeywordlApproachl[23:48]
Pageslforladditionallpractice
Modulel7:l7.11.1-ProbabilityloflDependentlEvents

Question
Alhospital’slfinanciallreimbursementlpayorlmixlindicatesl35%loflthe
patientslhavelMedicarelandl15%lhavelMedicaid.lOflthoselwholhavelM
edicare,ltherelislal10%lchanceltheylalsolhavelMedicaid.lWhatlislthelpr
obabilitylthatlalhospitallpatientlhaslbothlMedicarelandlMedicaid?
a. 0.015
b. 0.035
c. 0.005
d. 0.5

Answer
0.035
Brieflexplanation
P(MedicarelANDlMedicaid)l=lP(Medicare)l×lP(Medicaidl|lMedicare)
=lllllll0.35lllllll ×lllllllllllllllll0.10lllllllll =l0.035.
Note:lWhenlcomputinglanl“and”lprobability,lyoulmultiply.llThelsecond
factorlyouluselislalconditionallprobability,lwhichlislthelcorrectlthingltoldolasl
MedicaidlandlMedicarelarelnotlindependentlevents.ll(Seelpagel7.11.2linlMi
ndEdgelforlexamplesloflhowltolverifyltheldependencelofltwolevents.)
Videos
ANDlRulelvideol[8:49],llANDlmeansl“Multiply”l[10:12],landllAND,lOR,l&lIFlPr
obabilities:lKeywordlApproachl[23:48]
Pageslforladditionallpractice
Modulel7:l7.11.1-ProbabilityloflDependentlEvents