CSLB CONCRETE C8 LICENSE PRACTICE TEST - QUESTIONS WITH 100- CORRECT ANSWERS

CSLB CONCRETE C8 LICENSE PRACTICE TEST
#1 2024-2025 QUESTIONS WITH 100% CORRECT
ANSWERS

WhatPisPthePvolumePofPaPcylinderPifPthePdiameterPequalsP3PfeetPandPthePlengthPequalsPtoP12Pfeet?P-
PcorrectPanswer-84.78PcubicPfeet




Explanation:
ThereParePtwoPwaysPtoPsolvePthePproblem.PHowever,PregardlessPofPwhichPmethodPisPused,PyouPneedPtoPfirstP
determinePthePareaPofPthePcirclePthenPmultiplyPitPbyPthePlength.TraditionalPMethodUsePthePfollowingPformul
a:AreaPofPthePcircleP=PπPxPrPxPrWherePπP=P3.14PandPradiusP(r)P=P1.5PfeetP(halfPofPthePdiameterPlength)AreaP=P
3.14PxP1.5PxP1.5AreaP=P7.065Psq.Pft.MultiplyPareaPbyPthePlengthPtoPfindPthePvolume.7.065PxP12P=P84.78Short
cutPMethodAreaPofPthePcirclePisP78.5%PofPthePsquare.PTreatPthePcirclePasPaPsquarePandPsolvePforPtheParea.Fin
dPthePareaPofPthePsquarePinsteadPofPthePcircle.3'PxP3'P=P9Psq.Pft.SincePcirclePisP78.5%PofPthePsquare,PmultiplyP
areaPofPthePsquarePbyP78.5%P(orP.785PifPtherePisPnoPpercentagePsignPonPthePcalculator).9Psq.Pft.PxP.785P=P7.06
5PsquarePfeetMultiplyPareaPbyPthePlengthPtoPfindPthePvolume.7.065PxP12P=P84.78PcubicPfeet


WhereParePspiralPrebarPtiesPused?P-PcorrectPanswer-InProundPcolumns


ControlPjointsPinPsidewalksPshouldPbePspacedPatPwhatPintervals?P-PcorrectPanswer-
EqualPtoPthePwidthPofPthePslab


Explanation:
GenerallyPthePcontrolPjointsPinPsidewalksPshouldPbePspacedPequalPtoPthePwidthPofPthePslab,PbutPnotPmorePtha
nP6PfeetPapart.


OnePcubicPfootPofPcementPweighsPapproximately:P-PcorrectPanswer-95Plbs


HowPmanyPcubicPyardPofPconcretePisPrequiredPforPaP4"PslabPwithPthePdiameterPofP15Pfeet?P-PcorrectPanswer-
2P½PcubicPyards


Explanation:
TraditionalPMethodUsePthePfollowingPformula:AreaPofPthePcircleP=PπPxPrPxPrWherePπP=P3.14PandPradiusP(r)P
=P7.5PfeetP(halfPofPthePdiameterPlength)AreaP=P3.14PxP7.5PxP7.5AreaP=P176.625Psq.Pft.MultiplyPareaPbyPthePd

, epthPofPthePslabP(inPfeet)PtoPfindPthePvolumePinPcubicPfeet.176.625PxP.333P=P58.82PcubicPfeetConvertPcubicPf
eetPintoPcubicPyards.58.82P÷P27P=P2.18PcubicPyardsSinceP2.18PisPnotPaPgivenPoption,ProundPupPthePnumberPt
oP2.5PcubicPyardsShortcutPMethodThisPproblemPcanPbePsolvedPusingPaPmuchPsimplerPmethod.PFirstPisPtoPfin
dPthePareaPofPthePsquare,PthenPconvertPitPintoPthePareaPofPthePcirclePbyPmultiplyingPitPbyP78.5%.AreaPofPthePs
quareP=P15'PxP15'P=P225PsquarePfeetAreaPofPthePcircleP=P225PxP.785P=P176.625PsquarePfeetDividePthePvolume
PbyP81PtoPsolvePforPthePcubicPyardsPforPaP4"Pslab.176.625P÷P81P=P2.18PcubicPyardsSinceP2.18PisPnotPaPgivenP

option,ProundPupPthePnumberPtoP2.5PcubicPyards


ThePnormalPtolerancePforPthePlocationPofPbendsPandPendsPofPreinforcingPbarPis:P-PcorrectPanswer-+/-
P2Pinches




HowPmanyPcubicPyardsPofPbackfillParePrequiredPforPaP3'PxP5'Ptrench,P1500PftPlong,PwithPaP1PfootPdiameterPpip
e?P-PcorrectPanswer-789.72


Explanation:
StepP1.PFindPthePnetPfacePareaPofPthePtrenchPdeductingPforPpipe.FacePareaPincludingPpipe:P3PxP5P=P15PsquareP
feetAreaPofPthePpipe:P𝐴=𝜋𝑟2AP=P3.14PxP.5PxP.5AP=P0.785FindPthePfacePareaPofPthePtrenchPminusPareaPofPtheP
pipe,PwhichPwillPgivePyouPthePnetPareaPforPthePbackfill.15P-
P0.785P=P14.215StepP2.PFindPthePtotalPvolumePofPthePbackfill.14.215PxP1500P=P21322.5PcubicPfeetConvertPt

hePvolumePintoPcubicPyards.21322.5P÷P27P=P789.72PcubicPyards


WhenPcanPthePlivePloadPbePcalculatedPbyPmultiplyingPthePheight,PwidthPandPlengthPofPaPpourPandPdividingPb
yPthePdeadload?P-PcorrectPanswer-Never


TensilePstrengthPinPconcretePisPachievedPby:P-PcorrectPanswer-ThePusePofPsteelPreinforcement.


ReferPtoPthePhousePplan.PWhatPisPthePtotalPcostPforPthePfoundationPslabPifPthePcontractorPchargesP$3.54PperPs
quarePfoot?P-PcorrectPanswer-$6524.90


Explanation:
ThePeasiestPwayPtoPsolvePforPthePareaPofPthePslabPisPtoPimagePaPfullPrectanglePofPthePslabPandPsubtractPvoidPar
easPfromPthePareaPofPthePslab.


RectangleParea:P28.167'PxP71.5'=P2013.94PsqPftLeftPvoidParea:P6.667'PxP1.83'P=P12.2PsqPftCenterPvoidParea:P1
1.5'PxP1.83'P=P21.045PsqPftRightPvoidParea:P9.167'PxP15'P=P137.505NetPareaPofPthePfoundationPslab:P2013.94P
-P12.2P-P21.045P-P137.505P=P1843.19PsqPft.CalculatePthePpricePofPthePslab.1843.19PsqPftPxP$3.54P=P$6524.90