Electrical Field
Any charge has associated electric
field
·
an
when that
another
charge interacts
w/ this
field charge
·
, will experience
a
force
2 STEP FORCE
1) Field is created
2) Force to
field
any charged object
is applied in the
The electrical Q is
field at distance
from Single Charge
·
a r a
°
given by : E = R1Q1 /r =
E electric
field
:
distance
separating charges
↓=
* This the effect the (Q)
single charge of Q describes of one
charge
its
on
surroundings
* Also describes the
resulting electric
force applied on another
charge
9 placed in the field
** the field points away from positive charges and points
electric
towards
negative charges
↑ ↑
Y
-Er The direction
of the electric field is defined
e + >
-
F
↑ 44d as the direction that the
positive charge
would move
if it was
placed at that location
& its
always directed in the direction that the positive
charge would be pushed pulled if placed in the or
space Surrounding the change
#
what is the electric distance 1 9 X0-Om from
field at a
of . an
electron ?
E = (k) /Q) = 14 . 0 X10") (1 . 6 x 10 4) = 3488914 668 .
-8) X100 N
:
r z
(1 9
. X10 = 4 . 0 towards
electron
, Q # 1 . 2
what the electric twice the distance
is
field at
away from
the
electron ?
*
E = (k) /Q) = (4 0x10 .
%
) (1 . 6x10 -14) = 3 00 .
X10-2
2(r)2 2 ( 1 P . X10-0)
= (12) (Q)
4 0x108
°
E
2
12r) . = 1 .
0 X10 NIC
= (()(Q) 4
4 ~2
=
j. =
SAMPLEQ#14 4 .
electric distance X10 "om
field at at 1 . 5
from proton ?
E = (12) /Q) (4 0 X10") (1 6 X 10")
X10" N
=
6 4
. .
= .
↓ 2 1 S . x 10" °)2
Direction
of electric field forces and fields
#
positive charge electron F is parallel to electric field :
>
-
>°
-
A
negative charge electron = F is in the opposite direction to E
N
* The direction
F =
q
a
the electric
of field is -
>
defined as the direction that a
positive
&
charge would move
if it was
placed at
t
that location -
&
a x
Q #2
what is the electric electron if it
force experienced by an is
1 9X10'm from another electron ?
.
F qc-
°
-
E (4 0x100) =
electro
.
=
F ( 1 6 x 10 9)(4 0x104)
-
= -
.
.
13
6 4
-
= . x 10
R
*The value is I because opposites attract
q
* Also because the electric field moves towards the positive Charge
Any charge has associated electric
field
·
an
when that
another
charge interacts
w/ this
field charge
·
, will experience
a
force
2 STEP FORCE
1) Field is created
2) Force to
field
any charged object
is applied in the
The electrical Q is
field at distance
from Single Charge
·
a r a
°
given by : E = R1Q1 /r =
E electric
field
:
distance
separating charges
↓=
* This the effect the (Q)
single charge of Q describes of one
charge
its
on
surroundings
* Also describes the
resulting electric
force applied on another
charge
9 placed in the field
** the field points away from positive charges and points
electric
towards
negative charges
↑ ↑
Y
-Er The direction
of the electric field is defined
e + >
-
F
↑ 44d as the direction that the
positive charge
would move
if it was
placed at that location
& its
always directed in the direction that the positive
charge would be pushed pulled if placed in the or
space Surrounding the change
#
what is the electric distance 1 9 X0-Om from
field at a
of . an
electron ?
E = (k) /Q) = 14 . 0 X10") (1 . 6 x 10 4) = 3488914 668 .
-8) X100 N
:
r z
(1 9
. X10 = 4 . 0 towards
electron
, Q # 1 . 2
what the electric twice the distance
is
field at
away from
the
electron ?
*
E = (k) /Q) = (4 0x10 .
%
) (1 . 6x10 -14) = 3 00 .
X10-2
2(r)2 2 ( 1 P . X10-0)
= (12) (Q)
4 0x108
°
E
2
12r) . = 1 .
0 X10 NIC
= (()(Q) 4
4 ~2
=
j. =
SAMPLEQ#14 4 .
electric distance X10 "om
field at at 1 . 5
from proton ?
E = (12) /Q) (4 0 X10") (1 6 X 10")
X10" N
=
6 4
. .
= .
↓ 2 1 S . x 10" °)2
Direction
of electric field forces and fields
#
positive charge electron F is parallel to electric field :
>
-
>°
-
A
negative charge electron = F is in the opposite direction to E
N
* The direction
F =
q
a
the electric
of field is -
>
defined as the direction that a
positive
&
charge would move
if it was
placed at
t
that location -
&
a x
Q #2
what is the electric electron if it
force experienced by an is
1 9X10'm from another electron ?
.
F qc-
°
-
E (4 0x100) =
electro
.
=
F ( 1 6 x 10 9)(4 0x104)
-
= -
.
.
13
6 4
-
= . x 10
R
*The value is I because opposites attract
q
* Also because the electric field moves towards the positive Charge
