MATH 110 Module 4 Exam.| PORTGE LEARNING

Stati sti cs - Portage Online Summer 2018


MATH 110 Module 4 Exam.| PORTGE LEARNING

Module 4 Exam
Exam Page 1
A factory has eight safety systems. During an emergency, the probability of any one
of the safety systems failing is .08. What is the probability that six or more safety
systems will fail during an emergency?


f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-
p)^n-x)) ) n = 8
x = 6, 7, 8 (number of failures)
p = 0.08


6 failures:
n=8
x=6
p = 0.8
n-x = 8-6 = 2
( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2 x 10^-6


7 failures:
n=8
x=7
p = 0.8
n-x = 8-7 = 1
( (8!) / (7!(1)!) ) x ( (0.08^7) x ((1-0.08)^1)) ) = 1.54 x 10^-7


8 failures:
n=8
x=8
p = 0.8
n-x = 8-8 = 0
( (8!) / (8!(0)!) ) x ( (0.08^8) x ((1-0.08)^0)) ) = 1.68 x 10^-9




f(6) = 6.21 x 10^-6


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, Stati sti cs - Portage Online Summer 2018



f(7) = 1.54 x 10^-7
f(8) = 1.68 x 10^-9


(6.21 x 10^-6) + (1.54 x 10^-7) + (1.68 x 10^-9) = 6.355x10^-6


Probability of 6,7, and 8 failing during an emergency = 6.36 x 10^-6




Answer Key
A factory has eight safety systems. During an emergency, the probability of any one of the safety systems
failing is .08. What is the probability that six or more safety systems will fail during an emergency?




Exam Page 2
Find each of the following probabilities:


a. Find P(Z ≤ 1.27) .


P(Z ≤ 1.27) = 0.89796




This study source was downloaded by 100000834306259 from CourseHero.com on 04-20-2022 03:01:46 GMT -05:00


https://www.coursehero.com/file/32343987/Module-4-Examdocx/