100% de satisfacción garantizada Inmediatamente disponible después del pago Tanto en línea como en PDF No estas atado a nada 4.2 TrustPilot
logo-home
Resumen

Summary MATH 225N Week 5 Assignment: Applications of the Normal Distribution – Excel (2020) solution guide.

Puntuación
-
Vendido
-
Páginas
22
Subido en
02-04-2022
Escrito en
2021/2022

MATH 225N Week 5 Assignment: Applications of the Normal Distribution – Excel (2020) solution guide.

Institución
Grado










Ups! No podemos cargar tu documento ahora. Inténtalo de nuevo o contacta con soporte.

Escuela, estudio y materia

Institución

Información del documento

Subido en
2 de abril de 2022
Número de páginas
22
Escrito en
2021/2022
Tipo
Resumen

Temas

Vista previa del contenido

Stuvia.com - The Marketplace to Buy and Sell your Study Material




MATH 225N Week 5 Assignment: Applications
of the Normal Distribution – Excel

Question
Sugar canes have lengths, X , that are normally distributed with mean 365.45
centimeters and standard deviation 4.9 centimeters. What is the probability of the length
of a randomly selected cane being between 360 and 370 centimeters?

 Round your answer to four decimal places.




The mean is μ=365.45 , and the standard deviation is σ=4.9 . As the probability
between two values is to be calculated, subtract the probability of the lower value from the
higher value. In this case, you have to use the NORMDIST function twice.

1. Open Excel and click on any empty cell. Click Insert function, fx .

2. Search for NORMDIST in the search for a function dialog box and click GO.

3. Make sure NORMDIST is on top in select a function. Then click OK.

4. In the function arguments of NORMDIST function, enter 370 for X , 365.45 for
Mean, 4.9 for Standard_dev, and TRUE for Cumulative, all for the higher value of X .
Thus, the answer, rounded to four decimal places, is 0.8234 .

5. Click on any other empty cell. Click Insert function, fx .

6. Search for NORMDIST in the search for a function dialog box and click GO.

7. Make sure NORMDIST is on top in select a function. Then click OK.

8. In the function arguments of NORMDIST function, enter 360 for X , 365.45 for
Mean, 4.9 for Standard_dev, and TRUE for Cumulative, all for the lower value of X .
Thus, the answer, rounded to four decimal places, is 0.1330 .




Downloaded by: dennys |
Distribution of this document is illegal

, Stuvia.com - The Marketplace to Buy and Sell your Study Material




Now subtract, 0.8234−0.1330=0.6904 . Thus, the probability of the length of a
randomly selected cane being between 360 and 370 centimeters is 0.6904 .


Question
The number of miles a motorcycle, X, will travel on one gallon of gasoline is
modeled by a normal distribution with mean 44 and standard deviation 5. If
Mike starts a journey with one gallon of gasoline in the motorcycle, find the
probability that, without refueling, he can travel more than 50 miles.

Round your answer to four decimal places.

The mean is μ=44, and the standard deviation is σ=5. The probability that
Mike can travel, without refueling, more than 50 miles is shown below.




A normal curve is over a horizontal axis and is divided into 3 regions. Vertical
line segments extend from the horizontal axis to the curve at the mean,
44and at 50. The right region is shaded.




First find the probability to the left of 50 and subtract from 1.

1. Open Excel and click on any empty cell. Click Insert function, fx.




Downloaded by: dennys |
Distribution of this document is illegal

, Stuvia.com - The Marketplace to Buy and Sell your Study Material




2. Search for NORMDIST in the search for a function dialog box and click
GO.

3. Make sure NORMDIST is on top in select a function. Then click OK.

4. In the function arguments of NORMDIST function, enter 50 for X, 44 for
Mean, 5 for Standard_dev, and TRUE for Cumulative.

This probability, rounded to four decimal places, is 0.8849. Now
subtract, 1−0.8849=0.1151. Thus, the desired probability is
P(X>50)=0.1151.

Question
A worn, poorly set-up machine is observed to produce components whose
length X follows a normal distribution with mean 14 centimeters and
variance 9. Calculate the probability that a component is at least 12
centimeters long.

Round your answer to four decimal places.

The mean is μ=14, and the standard deviation is σ=9–√=3.

1. Open Excel and click on any empty cell. Click Insert function, fx.

2. Search for NORMDIST in the search for a function dialog box and click
GO.

3. Make sure NORMDIST is on top in select a function. Then click OK.

4. In the function arguments of NORMDIST function, enter 12 for X, 14 for
Mean, 3 for Standard_dev, and TRUE for Cumulative. The probability,
rounded to four decimal places, is P(X<12)≈0.2525.

P(X≥12), so subtract from 1 to get
The desired probability is
P(X≥12)=1−0.2525=0.7475.




Downloaded by: dennys |
Distribution of this document is illegal
$19.49
Accede al documento completo:

100% de satisfacción garantizada
Inmediatamente disponible después del pago
Tanto en línea como en PDF
No estas atado a nada

Conoce al vendedor
Seller avatar
BRIANEKAKA

Conoce al vendedor

Seller avatar
BRIANEKAKA LIBERTY UNIVERSITY
Seguir Necesitas iniciar sesión para seguir a otros usuarios o asignaturas
Vendido
4
Miembro desde
3 año
Número de seguidores
3
Documentos
49
Última venta
8 meses hace

0.0

0 reseñas

5
0
4
0
3
0
2
0
1
0

Recientemente visto por ti

Por qué los estudiantes eligen Stuvia

Creado por compañeros estudiantes, verificado por reseñas

Calidad en la que puedes confiar: escrito por estudiantes que aprobaron y evaluado por otros que han usado estos resúmenes.

¿No estás satisfecho? Elige otro documento

¡No te preocupes! Puedes elegir directamente otro documento que se ajuste mejor a lo que buscas.

Paga como quieras, empieza a estudiar al instante

Sin suscripción, sin compromisos. Paga como estés acostumbrado con tarjeta de crédito y descarga tu documento PDF inmediatamente.

Student with book image

“Comprado, descargado y aprobado. Así de fácil puede ser.”

Alisha Student

Preguntas frecuentes