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Exam (elaborations) TEST BANK FOR Statistical Physics of Fields Solution Manual By Mehran Kardar

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TEST BANK FOR Statistical Physics of Fields Solution Manual By Mehran Kardar Problems & Solutions for Statistical Physics of Fields Updated July 2008 by Mehran Kardar Department of Physics Massachusetts Institute of Technology Cambridge, Massachusetts 02139, USA Table of Contents 1. Collective Behavior, From Particles to Fields . . . . . . . . . . . . . . . . 1 2. Statistical Fields . . . . . . . . . . . . . . . . . . . . . . . . . . . . 18 3. Fluctuations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31 4. The Scaling Hypothesis . . . . . . . . . . . . . . . . . . . . . . . . . 55 5. Perturbative Renormalization Group . . . . . . . . . . . . . . . . . . . 63 6. Lattice Systems . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 90 7. Series Expansions . . . . . . . . . . . . . . . . . . . . . . . . . . 106 8. Beyond Spin Waves . . . . . . . . . . . . . . . . . . . . . . . . . . 132 Solutions to problems from chapter 1- Collective Behavior, From Particles to Fields 1. The binary alloy: A binary alloy (as in β brass) consists of NA atoms of type A, and NB atoms of type B. The atoms form a simple cubic lattice, each interacting only with its six nearest neighbors. Assume an attractive energy of −J (J > 0) between like neighbors A − A and B − B, but a repulsive energy of +J for an A − B pair. (a) What is the minimum energy configuration, or the state of the system at zero temperature? • The minimum energy configuration has as little A-B bonds as possible. Thus, at zero temperature atoms A and B phase separate, e.g. as indicated below. A B (b) Estimate the total interaction energy assuming that the atoms are randomly distributed among the N sites; i.e. each site is occupied independently with probabilities pA = NA/N and pB = NB/N. • In a mixed state, the average energy is obtained from E = (number of bonds) × (average bond energy) = 3N ·

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, Problems & Solutions



for

Statistical Physics of Fields



Updated July 2008

by

Mehran Kardar
Department of Physics
Massachusetts Institute of Technology
Cambridge, Massachusetts 02139, USA

, Table of Contents


1. Collective Behavior, From Particles to Fields . . . . . . . . . . . . . . . . 1
2. Statistical Fields . . . . . . . . . . . . . . . . . . . . . . . . . . . . 18
3. Fluctuations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31
4. The Scaling Hypothesis . . . . . . . . . . . . . . . . . . . . . . . . . 55
5. Perturbative Renormalization Group . . . . . . . . . . . . . . . . . . . 63
6. Lattice Systems . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 90
7. Series Expansions . . . . . . . . . . . . . . . . . . . . . . . . . . 106
8. Beyond Spin Waves . . . . . . . . . . . . . . . . . . . . . . . . . . 132

, Solutions to problems from chapter 1- Collective Behavior, From Particles to Fields

1. The binary alloy: A binary alloy (as in β brass) consists of NA atoms of type A, and
NB atoms of type B. The atoms form a simple cubic lattice, each interacting only with its
six nearest neighbors. Assume an attractive energy of −J (J > 0) between like neighbors
A − A and B − B, but a repulsive energy of +J for an A − B pair.
(a) What is the minimum energy configuration, or the state of the system at zero temper-
ature?
• The minimum energy configuration has as little A-B bonds as possible. Thus, at zero
temperature atoms A and B phase separate, e.g. as indicated below.




A B




(b) Estimate the total interaction energy assuming that the atoms are randomly distributed
among the N sites; i.e. each site is occupied independently with probabilities pA = NA /N
and pB = NB /N .
• In a mixed state, the average energy is obtained from

E = (number of bonds) × (average bond energy)
= 3N · −Jp2A − Jp2B + 2JpA pB

 2
NA − NB
= −3JN .
N


(c) Estimate the mixing entropy of the alloy with the same approximation. Assume
NA , NB ≫ 1.
• From the number of ways of randomly mixing NA and NB particles, we obtain the
mixing entropy of  
N!
S = kB ln .
NA !NB !
Using Stirling’s approximation for large N (ln N ! ≈ N ln N − N ), the above expression can
be written as

S ≈ kB (N ln N − NA ln NA − NB ln NB ) = −N kB (pA ln pA + pB ln pB ) .

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